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3 years ago

What is 28 divided by 4?

Mathematics

2 answers:

koban [17]3 years ago

8 0

The answer is seven.

yan [13]3 years ago

6 0

Answer: 7

Step-by-step explanation:

7•4=28 therefor 28\4= 7

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Rosa's test scores are 78, 92, 88, and 89. What must she score on her next test to have an average of 90? A) 95 B) 97 C) 99 D) 1

Morgarella [4.7K]

Answer: D

Step-by-step explanation:

Let x represent the score on her next test

$\frac{78 + 92 + 88 + 89 + x}{5} = 90$

$(5)\frac{78 + 92 + 88 + 89 + x}{5} = (5)90$

78 + 92 + 88 + 89 + x = 5(90)

347 + x = 450

-347 -347

x = 103

3 0

3 years ago

Hurry please! The table shows the results of a survey about favorite movie theater snacks.Write a fraction in simplest form that

Basile [38]

So if 24 people chose popcorn and there is a total of 60 people surveyed, the fraction would be 24/60. You still need to simplify the fraction, so divide 24/60 by 4 to get 6/15. Hope this helps. -S

4 0

3 years ago

In the diagram of circle C, what is the measure of 21?

kondaur [170]

Answer:

If I know what diagram you're referring to, which I believe I do, the answer is: ∠1=(1/2)[106°-36°]=35°

4 0

3 years ago

PLEASE I NEED HELP

notka56 [123]

You would transform 5x + 2x into the same term with the associative property, adding like terms. If you subsitute the different values into the expressions you notice that both have a rate of change of 7 like an arithmetic sequence. To see if any value will make the two expressions equal you make them equal to each other.

5x + 2x = 7x -1

7x = 7x - 1

0 = -1

No they will never have be a solution to both expressions to make them equal because they're parallel to each other.

7 0

3 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

3 years ago