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IrinaK [193]
3 years ago
5

What is the value of x when x^2=10?

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0
X^2=10
square root it
sqrt(x^2) = sqrt (10)
x= sqrt(10)
Cannot reduce more
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Think about a population mean that you may be interested in and propose a hypothesis test problem for this parameter. Gather app
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Answer:

There is no sufficient evidence to conclude that population mean number of times that adults go out for dinner each week is less than 1.5

Step-by-step explanation:

From the question we are told that

   The  population mean is  less than  1.5

   The sample size is  n  =  7

   The sample data is   2, 0, 1, 5, 0, 2, and 3

Generally the sample mean is mathematically represented as  

     \=  x =  \frac{ \sum x_i }{ n }

=>  \=  x =  \frac{ 2 +  0 +  1 +  5 +  0 +  2 +   3 }{ 7 }

=>  \=  x =  1.857

Generally the standard deviation is mathematically represented as

      \sigma  =  \sqrt{\frac{\sum (x_i - \= x)^2}{n} }

=>   \sigma  =  \sqrt{\frac{ (2 -   1.857)^2 +  (0 -   1.857)^2 +\cdots  (3 -   1.857)^2}{7} }

=>   \sigma  =  1.773

The null hypothesis is  H_o :  \mu  =  1.5

The alternative hypothesis is H_a  :  \mu  < 1.5

Generally the test statistics is mathematically represented as

     z  =  \frac{\= x  -  \mu }{ \frac{\sigma }{\sqrt{n} } }

=>   z  =  \frac{\= x  - 1.857 }{ \frac{1.773 }{\sqrt{7} } }  

=>z =  0.53

Generally the p-value is mathematically represented as

      p-value  =  P(z  < 0.53 )

From the z-table  

        P(z  <  0.53 ) =  0.70194

So

       p-value  =  0.70194

From the values obtained we see that p-value  >  0.05  

Here there is no sufficient evidence to conclude that population mean number of times that adults go out for dinner each week is less than 1.5

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