Question

alt=" {x}^{2} - 22x + 121" align="absmiddle" class="latex-formula">

Answer 1

Let's factor x^2−22x+121

The middle number is -22 and the last number is 121. Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks? We need two numbers that...

Add together to get -22

Multiply together to get 121

Can you think of the two numbers?

Try -11 and -11:

-11+-11 = -22

-11*-11 = 121

Fill in the blanks in

(x+_)(x+_)

with -11 and -11 to get...

(x-11)(x-11)

Answer: (x-11)(x-11)

Hope this helps!!!