alt=" {x}^{2} - 22x + 121" align="absmiddle" class="latex-formula">
1 answer:
Let's factor x^2−22x+121
The middle number is -22 and the last number is 121. Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks? We need two numbers that...
Add together to get -22
Multiply together to get 121
Can you think of the two numbers?
Try -11 and -11:
-11+-11 = -22
-11*-11 = 121
Fill in the blanks in
(x+_)(x+_)
with -11 and -11 to get...
(x-11)(x-11)
Answer: (x-11)(x-11)
Hope this helps!!!
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