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serg [7]
3 years ago
12

Data Set: {60, 30, 35, 30,25}

Mathematics
1 answer:
GrogVix [38]3 years ago
3 0
30 is the correct answer
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Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

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3 years ago
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3 0
3 years ago
In a right triangle, the value of cos B = 3/5. What is the value of sin B?
ozzi

Answer:

4/5

Step-by-step explanation:

cos B = 3/5

cos Ф = adjacent/hypothesis

hypothesis ² = adjacent² + opposite²

5²= 3²+ o²

25 = 9+o²

25-9=o²

16 = o²

√16 = o = 4

Sin B = opposite/hypothesis = 4/5

7 0
3 years ago
If 5 of 22 students are hearing impaired - what fraction of students are hearing impaired
Shtirlitz [24]
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find the sum of all possible four digit numbers that can be formed using the digits 2,4,5,6,7 and 8 with no repeated digits
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1+1
2+2
5+0
3+3
6+2-1
4+4
8 0
2 years ago
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