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3 years ago

Does anyone know how to answer this?

Mathematics

2 answers:

Over [174]3 years ago

4 0

Answer:

PQS = 59.5

RQS = 59.5

Step-by-step explanation:

Bisects means cuts in half meaning you have to divide the 119 by 2 to get each measure.

posledela3 years ago

3 0

Answer:

PQS and RQS are both 59.5 degrees

Step-by-step explanation:

Bisect means divide two parts EQUALLY so 119 divided by 2 is 59.5

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Solve the system of equations. 5x + 3y = 4 2x + y = 1

stepladder [879]

Answer:

(-1, 3)

Step-by-step explanation:

5x + 3y = 4

2x + y = 1 ⇒ y=1-2x

5x+3(1-2x)=4
5x+3-6x=4
-x=4-3
-x=1
x=-1
y= 1-2(-1)= 1+2=3

3 0

3 years ago

Solve for the missing x coordinate above

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The unknown vertex is on the perpendicular bisector of the opposite side. So the x coordinate is the same as that of the midpoint, x=(18+52)/2=35.

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4 years ago

What expression is equivalent to? Screenshots attached. Please help!

Galina-37 [17]

Answer:

the correct option is C i.e. $8x^4yz^4\sqrt{2yz}$

Step-by-step explanation:

We need to solve the expression :

$\sqrt{128x^8y^3z^9}$

Factors of 128 are: 2x2x2x2x2x2x2

and we know √ = 1/2

and √a.b = √a.√b

Solving:

$=\sqrt{128x^8y^3z^9}\\\\=\sqrt{128} \sqrt{x^8} \sqrt{y^3} \sqrt{z^9}\\=\sqrt{2x2x2x2x2x2x2}\sqrt{x^8} \sqrt{y^2.y} \sqrt{z^8.z}\\=\sqrt{2^2x2^2x2^2x2}\sqrt{x^8} \sqrt{y^2.y} \sqrt{z^8.z}\\=(2^2)^{1/2} (2^2)^{1/2}(2^2)^{1/2} (2)^{1/2} (x^8)^{1/2} (y^2)^{1/2} (y)^{1/2} (z^8)^{1/2} z^{1/2}\\=2.2.2.(2)^{1/2}x^4y(y)^{1/2}z^4(z)^{1/2}\\=8x^4yz^4\sqrt{2yz}$

So, the correct option is C i.e. $8x^4yz^4\sqrt{2yz}$

7 0

3 years ago

An investment earning interest at the rate of 10%, compounded continuously, will double in t years. Find t. Use the formula , wh

Andre45 [30]

Answer:

I have attached the formula solved for years (or time).

We'll say principal = 100 and total = 200

Years = ln (200 / 100) / .1

Years = ln (2) / .1

Years = 0.69314718056 / .1

Years = 6.9314718056

Step-by-step explanation:

8 0

3 years ago

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3 years ago

Does anyone know how to answer this?​

Does anyone know how to answer this?