Answer:
552
Step-by-step explanation:
This is a problem of permutation which can be solved by rule of fundamental counting principle.
This principle states that if there "m" ways of doing one thing and "n" ways of doing other. Then no. of ways in which both the things can be done together is "m*n". This can be extended for m, n, p,r, s things and so on.
example: if there are 5 shirts and 3 trousers then number of ways in which the shirts and trousers can be worn is 5*3 = 15 ways.
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The given problem is on similar concepts.
here 6 short stories, 4 novels, and 23 poems have to be assigned to his class.
Thus it can be done in 6*4*23 = 552 ways.
A) There are 36 possible outcomes.
b) The probability of a sum of 6 is 5/36.
c) She should roll a sum of 7 45 times.
d) She should roll a sum of 10 45 times.
Explanation
a) There are 6 outcomes for the first die and 6 outcomes for the second one. By the fundamental counting principle, there are 6*6 = 36 outcomes for both dice together.
b) The ways to get a sum of 6 are:
1&5; 2&4; 3&3; 4&2; 5&1. There are 5 possibilities out of a total of 36, or 5/36.
c) The ways to get a sum of 7 are:
1&6; 2&5; 3&4; 4&3; 5&2; 6&1. There are 6 out of 36, or 6/36=1/6. Since she is rolling the dice 150 times, she should get a sum of 6
1/6(150) = 150/6 = 45 times.
d) The ways to get a sum of 10 or more are:
4&6; 5&5; 6&4; 5&6; 6&5; 6&6
There are 6 ways out of 36, or 6/36 = 1/6. Since she is rolling the dice 150 times, she should get a sum of 10 or more
1/6(150) = 150/6 = 45 times.