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2 years ago

13

Use the calculator to find the product. (1. 466 × 10–8)(5. 02 × 105) What is the coefficient of the product? What is the exponen

t of the power in the product?.

2 answers:

mestny [16]2 years ago

6 0

The product of the factors in the given expression comes to be $7.35932 *10^{-3}$ .

The given expression is:

$(1.466*10^{-8} )(5.02*10^5)$

We can rewrite the given expression as

$(1.466*5.02)(10^{-8} *10^5)$

<h3>What is the exponent addition rule? </h3>

If we have two numbers with the same base we can write the product of the numbers as a single base followed by the addition of exponents.

$a^m*a^n = a^{m+n}$

$1.466*5.02=7.35932$

$10^{-8} *10^5 = 10^{-3}$ ....from exponent addition rule

So, $(1.466*10^{-8} )(5.02*10^5)=7.35932 *10^{-3}$

Therefore, the product of the factors in the given expression comes to be $7.35932 *10^{-3}$ .

To get more about exponents visit:

brainly.com/question/819893

Yuliya22 [10]2 years ago

5 0

Answer:

7.3593 and -3

Step-by-step explanation:

Got it right on the assignment.

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steposvetlana [31]

Answer:

-6 -7 -8 -9 -10

Step-by-step explanation:

anything that keeps going from there dont do anything like -5 -4 -3 -2 -1 because it would be wrong

any negative number that keeps increasing after -6

7 0

3 years ago

Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

<em>This has been shown in (c) above</em>

3 0

3 years ago

Any REAL help on #16 above??? Can someone check my answer?

babymother [125]

Answer:

The answer to your question is:th first option is correct.

Step-by-step explanation:

Here we have and hyperbola with center (0, 1), and the hyperbola is horizontal because x² is positive.

Equation

y - k = ± $\frac{b}{a} (x - h)$

Process

Find a, b

a² = 9

a = 3

b² = 5

b = √5

h = 0 and k = 1

Substitution

y - 1 = ± $\frac{√5}{3} (x - 0)$

Equation 1

y = $\frac{\sqrt{5} }{3} x + 1$

Equation 2

y = - $\frac{\sqrt{5} }{3} x + 1$

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3 years ago

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tigry1 [53]

5.95 is your answer. Have a wonderful day

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Papessa [141]

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Step-by-step explanation:

Hope this helps!

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3 years ago

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