Umbilical
point.
An
umbilic point, likewise called just an umbilic, is a point on a surface at
which the arch is the same toward any path.
In
the differential geometry of surfaces in three measurements, umbilics or
umbilical focuses are focuses on a surface that are locally round. At such
focuses the ordinary ebbs and flows every which way are equivalent,
consequently, both primary ebbs and flows are equivalent, and each digression
vector is a chief heading. The name "umbilic" originates from the
Latin umbilicus - navel.
<span>Umbilic
focuses for the most part happen as confined focuses in the circular area of
the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces
with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an
outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two
umbilics.</span>
Answer: m = -5/8
Step-by-step explanation:
The general equation for slope is rise over run, also known as:
m=(y2-y1)/(x2-x1)
From the points (x, y), we can get all the variables we need.
(-1, -7) gives us x1 = -1 and y1 = -7
(-9, -2) gives us x2 = -9 and y2 = -2
If we plug all the values in, we get:
m = (-2 - (-7))/(-9 - (-1))
m = (-2 + 7)/(-9 + 1) the negatives cancel
m = (5)/(-8)
m = -5/8
y=1.5x+3
Observing the graph
Let,
A(0,3) -----> this point is the y-intercept of the line
B(2,6)
We know that
The equation of the line into slope intercept form is equal to
y = mx + c
where
m is the slope
b is the y-coordinate of the y-intercept
In this problem
b=3
Find the slope of the line m
The formula to calculate the slope between two points is equal to
m = y2-y1 / x2-x1
substitute the values
m = 6-3 / 2-0
m = 3/2
m = 1.5
The equation of the line is
y= 1.5x+3
To know more about Slope
Refer this link:
brainly.com/question/3493733
#SPJ1
To isolate b, add a and subtract c to the entire equation:
D - a + c = -b
Muliply b by -1 to eliminate the negative:
-D + a - c = b
Just divide 1.36 by 8
0.17
