All categories

3 years ago

List the steps to solve this

Mathematics

1 answer:

miskamm [114]3 years ago

5 0

Answer:

Step-by-step explanation:

First, distribute the 2 to the 3z and -6 within the parenthesis.

You know have 6z -12/5 + 6 = 10

Subtract 6 from both sides of the equation

6z -12/5 = 4

Multiply 5 on both sides of the equation

6z -12 = 20

Add 12 to both sides of the equation

6z = 32

Divide by 6 on both sides of the equation

z = 32/6

Simplify

z = 16/3

I hope that this helps! :)

You might be interested in

Why does 69 + 74 + 71 + 69 + 74 + 78 + 70 = 505 and not 504?

Vesna [10]

Because, that's just how math works.

8 0

3 years ago

HELP ASAP: Factor By Grouping: 12a^3 - 9a^2 + 4a - 3

MAVERICK [17]

We have been given an expression $12a^3 - 9a^2 + 4a - 3$ . We are asked to factor the given expression by grouping.

First of all, we will make two groups of our expression as:

$(12a^3-9a^2)+( 4a - 3)$

Now we will factor of greatest common factor from each group.

$(3a^2\cdot 4a-3a^2\cdot 3)+( 4a - 3)$

$3a^2(4a-3)+1( 4a-3)$

Now we will factor out common terms $(4a-3)$ as:

$(4a-3)( 3a^2+1)$

Therefore, the factorized form of our given expression would be $(4a-3)( 3a^2+1)$ .

7 0

3 years ago

1. Find the value of x: (110) (618) 62 = 315 68

user100 [1]

Answer:

there that should help

Step-by-step explanation:

Download pdf

8 0

3 years ago

Express the vector ModifyingAbove Upper P 1 Upper P 2 with right arrowP1P2 in the form Bold v equals v 1 Bold i plus v 2 Bold j

Tatiana [17]

Answer:

$\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

Step-by-step explanation:

$\overrightarrow{P_1P_2}=(P_2-P_1)\cdot(\textbf{i},\textbf{j},\textbf{k})=(-5-0)\textbf{i}+(-3-1)\textbf{j}+(-9-(-3))\textbf{k}\\\\\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

3 0

3 years ago

In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0

3 years ago