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gavmur [86]
3 years ago
9

List the steps to solve this

Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

Step-by-step explanation:

First, distribute the 2 to the 3z and -6 within the parenthesis.

You know have 6z -12/5 + 6 = 10

Subtract 6 from both sides of the equation

6z -12/5 = 4

Multiply 5 on both sides of the equation

6z -12 = 20

Add 12 to both sides of the equation

6z = 32

Divide by 6 on both sides of the equation

z = 32/6

Simplify

z = 16/3

I hope that this helps! :)

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Factor each expression completely6x^2+x-2
Citrus2011 [14]
6x^2+x-2

first , set the function equal to zero

6x^2+x-2=0

now we can use this expression to factor

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

where a is 6, b is 1 and c -2

so, replacing

\begin{gathered} \frac{-(1)\pm\sqrt[]{1^2-4(6)(-2)}}{2(6)} \\  \\ \frac{-1\pm\sqrt[]{1+48}}{12} \\  \\ \frac{-1\pm\sqrt[]{49}}{12} \\  \\ x=\frac{-1\pm7}{12} \end{gathered}

x has two values

x_1=\frac{-1+7}{12}=\frac{1}{2}x_2=\frac{-1-7}{12}=-\frac{2}{3}

we have the two roots now we chang the sign and make the factor expression

(x-\frac{1}{2})(x+\frac{2}{3})

8 0
1 year ago
Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair
umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

<u>Maximum value occurs at 325 at the point (0, 325)</u>

<u>Step-by-step explanation:</u>

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0
3 years ago
What is the transformation of g(x)=3(2)-xfrom the parent function f(x)=2x?
lisov135 [29]
Shift of 6 units right, reflects over x-axis
4 0
3 years ago
Find all solutions to each quadratic equation
romanna [79]
I hope this helps you



2x^2-4x+7=0 a=2 b=-4 c= 7



disctirminant =b^2-4ac


disctirminant =(-4)^2-4.2.7


disctirminant = 16-56= -40


x=-b+square root of disctirminant ÷2a


x=4+2square root of (-10)/4


x=2+square root of (-10)/2


x'=4 -2 square root of (-10)/4


x'=2 -square root of (-10)/2
6 0
2 years ago
Which of the following values are solutions to the inequality x-7&lt; 5?x−7&lt;5?
Lunna [17]

Answer:

x>12

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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