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3 years ago

Absolute value of 19

Mathematics

2 answers:

marissa [1.9K]3 years ago

8 0

It is 19 because it is a positive

Anna007 [38]3 years ago

7 0

The absolute value of 19 is 19

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The area of the parallelogram is_______________

mars1129 [50]

Answer:

C) 384

Step-by-step explanation:

A=bh

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3 years ago

Read 2 more answers

Which pair of angles are corresponding angles?

Effectus [21]

Corresponding angles are angles that are the same, and occupy the same relative position.

1 and 2: Incorrect - These are supplementary angles

3 and 5: Incorrect - These are same-side interior angles

2 and 6: Correct - These are corresponding angles

4 and 7: Incorrect - These are alternate interior angles

Hope this helps!! :)

7 0

3 years ago

Find all real numbers $s$ such that $-2(s - 7) > 4s + 8$. Give your answer in interval notation.

Stolb23 [73]

Answer:

$s\in (-\infty,1)$

Step-by-step explanation:

Solve the inequality $-2(s - 7) > 4s + 8$

Use distributive property:

$-2s+14>4s+8$

Subtract 4s:

$-2s+14-4s>4s+8-4s\\ \\-6s+14>8$

Subtract 14:

$-6s+14-14>8-14\\ \\-6s>-6$

Divide by -6 (do not forget to change sign, because division by negative number changes the sign):

$s$

5 0

3 years ago

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

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3 years ago

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Ms. M feeds her fish 1/5 of food each day. There is 25 cups of cat food in the bag. How many days will the bag of cat food last?

Harlamova29_29 [7]

Answer is 5

first you do 1 divided by 5 then you times by 25

4 0

3 years ago