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This equation is in vertex form. Vertex form is y=a(x-h)^2+k, where (h,k) is the vertex. In this equation, h= -3, and k= -4. So, the vertex would be at (-3,-4). A tells us if the parabola will be positive or negative. In this case, it is positive, so the parabola opens upward. Then, you can solve for x-intercept by letting y=0 and solving for x. Then, you can find the y-intercept by setting x=0 and solving for y. Finally, graph the parabola.
answer.
Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
5x+2y=105x+2y=10 (1)
And 3x+2y=63x+2y=6 (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
15x+6y=3015x+6y=30 (3)
15x+10y=3015x+10y=30 (4)
Now subtract (4) from (3) we get:
-4y=0−4y=0
y=0y=0
Now, put y=0 in (1) equation:
5x+2(0)=105x+2(0)=10
5x=105x=10
x=2x=2
Hence, x=2 and y=0
Answer:
23 is the answer of the question
12/-30=8x
cross multiply
12x=-240
x=-20