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MArishka [77]
3 years ago
9

Need answers for 70-75

Mathematics
1 answer:
adoni [48]3 years ago
8 0

Answer:

70. 0

71. -54

72. 12

73. 86

74. 59

Step-by-step explanation:

To evaluate an expression, substitute specific values for the variables and simplify using Order of Operations.

70. c-3d becomes

(1)-3(\frac{1}{3}) = 1-(\frac{3}{3}) = 1-1 = 0

71. x+x^3-4x^4 becomes

2+2^3-4(2)^4 = 2+8-4(16) = 2+8-64=10-64=-54

72. 5a+3a^2 becomes

5(-3)+3(-3)^2 = -15 +3(9) = -15 + 27 = 12

73. F=\frac{9}{5}C+32 becomes

F=\frac{9}{5}(30)+32=\frac{270}{5}+32 = 54+32 = 86

74.  F=\frac{9}{5}C+32 becomes

F=\frac{9}{5}(15)+32=\frac{135}{5}+32 = 27+32 = 59

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Recall that \sin^2\theta+\cos^2\theta=1, which means

\cos\theta=\pm\sqrt{1-\sin^2\theta}=\pm\sqrt{1-\dfrac{16}{17}}=\pm\dfrac1{\sqrt{17}}

Since \tan\theta=\dfrac{\sin\theta}{\cos\theta}>0, and \sin\theta>0, it follows that \cos\theta>0 too, so you take the positive root:

\cos\theta=\dfrac1{\sqrt{17}}

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\cot\theta=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac1{\sqrt{17}}}{\frac4{\sqrt{17}}}=\dfrac14
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4 years ago
What is the numbers (3, 5) and (6, 9) placed on a graph
labwork [276]

When we want to draw a point on the graph we need to have a value of x and y i.e (x,y)

Step-by-step explanation:

We need to place the numbers (3,5) and (6,9) on graph.

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So, for given point (3,5) the value of x = 3 and y=5

For placing it on graph choose 3 on x-axis and 5 on y-axis, the place where both points meet is the point (3,5)

Similarly for point (6,9) the value of x = 6 and y=9

For placing it on graph choose 6 on x-axis and 9 on y-axis, the place where both points meet is the point (6,9)

The points place on graph are shown in figure attached.

Keywords: graph the points

Learn more about graph the points at:

  • brainly.com/question/3126500
  • brainly.com/question/7857079
  • brainly.com/question/10879401

#learnwithBrainly

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monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

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Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

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We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

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