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Rina8888 [55]
3 years ago
14

Determine for which class of lever the output force is always greater than the input force. for which class is the output force

always less than the input force?

Physics
2 answers:
umka2103 [35]3 years ago
5 0
The 3rd class lever is the <span>output force always less than the input force, becuase its mechanical advantage is always less than 1. this also due that in a 3rd class lever the effort arm is shorter than the load arm, that is why the output is lower than the input force. but 3rd class lever is a speed multiplier lever</span>
Ad libitum [116K]3 years ago
4 0

Answer:

  • <u>Second Class of lever:</u> The second class of the lever is considered the most efficient or have the most mechanical advantage in conveying more productivity or output while investing less input into the system.

Explanation:

<u>The second Class of lever:</u>

The second type of lever has the load,L in between the effort,E and the fulcrum,F. As the effort moves a larger distance to move the load a small distance. As there is more productivity or mechanical output in response to less input to the system.

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A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it aroun
nalin [4]

Answer:

Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz

Explanation:

Given data

Source Frequency fs=600Hz

Length r=1.0m

RPM=100 rpm

The speed of the generator is calculated as:

v_{s}=rw\\v_{s}=r(2\pi f)

Substitute the given values

v_{s}=(1.0m)2\pi (\frac{100}{60}rev/s )\\v_{s}=10.47m/s

For approaching generator the frequency is calculated as:

f_{+}=\frac{f_{s}}{1-\frac{v_{s}}{v} }\\f_{+}=\frac{600Hz}{1-\frac{10.47m/s}{343m/s} } \\f_{+}=620Hz

On the other hand,for the receding generator,Doppler's effect is expressed as:

 f_{-}=\frac{f_{s}}{1+\frac{v_{s}}{v} }\\f_{-}=\frac{600Hz}{1+\frac{10.47m/s}{343m/s} } \\f_{-}=580Hz

Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz

8 0
3 years ago
We know the frequency range of certain sounds are: 400-560 Hz, what are the ranges of wavelength in meters when the signal trans
Ksivusya [100]

Answer:

Range of wavelength will be 5.35\times 10^5m to 7.5\times 10^5m

Explanation:

We have given range of frequency is 400-560 Hz

Speed of the light c=3\times 10^8m/sec

We have to find the range of the wavelength of signal transmitted

Ween know that velocity is given by v=\lambda f, here \lambda is wavelength and f is frequency

So for 400 Hz frequency wavelength will be \lambda =\frac{c}{f}=\frac{3\times 10^8}{400}=7.5\times 10^5m

And wavelength for frequency 560 Hz \lambda =\frac{c}{f}=\frac{3\times 10^8}{560}=5.35\times 10^5m

So range of wavelength will be 5.35\times 10^5m to 7.5\times 10^5m

8 0
3 years ago
An object that is slowing down is accelerating.<br> True<br> False
Art [367]
Answer:

True

Explanation

When an object slows down the Acceleration is in the other direction which “ slows it down
8 0
3 years ago
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