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LuckyWell [14K]
1 year ago
6

In the Roman soldier model for refraction, what happens to the distance between the rows of each soldier once they enter the str

eam?
A. Not enough info
B. They are closer together
C. They stay the same distance
D. They are further apart
Physics
1 answer:
Anon25 [30]1 year ago
4 0

They pick up speed and move away from the usual.

Using meter sticks, a group of pupils makes a straight line (shoulder to shoulder) and connects to their closest neighbor. Two media are separated in the room by a strip of masking tape. Students can be seen moving normally in one of the media (on one side of the tape). The kids in the other medium (or on the opposite side of the tape) move very slowly and in baby stages. The class moves in the union in a straight line in the direction of the diagonal piece of masking tape. As they get close to the masking tape, the pupils stay in line. Each pupil immediately changes the speed of her or his walk as she or he reaches the tape.

learn more about distance: brainly.com/question/17273444

#SPJ1

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A batter hits a fly ball which leaves the bat 0.89 m above the ground at an angle of 62 ∘ with an initial speed of 29 m/s headin
KatRina [158]

consider the motion in Y-direction

v₀ = initial velocity = 29 Sin62 = 25.6 m/s

a = acceleration = - 9.8 m/s²

t = time of travel

Y = vertical displacement = - 0.89 m

using the equation

Y = v₀ t + (0.5) a t²

- 0.89 = (25.6) t + (0.5) (- 9.8) t²

t = 5.3 sec


consider the motion along the horizontal direction :

v₀ = initial velocity = 29 Cos62 = 13.6 m/s

a = acceleration = 0 m/s²

t = time of travel = 5.3 sec

X = horizontal displacement =?

using the equation

X = v₀ t + (0.5) a t²

X = (13.6) (5.3) + (0.5) (0) t²

X = 72.1 m


d = distance traveled by the center fielder to catch the ball = 107 - x = 107 - 72.1 = 34.9 m

t = time taken = 5.3 sec

v = speed of center fielder

using the equation

v = d/t

v = 34.9/5.3

v = 6.6 m/s

3 0
2 years ago
If you heat a fixed quantity of gas, which of the following statements are true?Check all that apply.a.The volume will always in
kherson [118]

Answer:

Explanation:

Given

there is fix Quantity of gas i.e. mass of gas is constant

From ideal gas Equation

PV=nRT

(a) volume always increases is not true as Pressure can also be increased .

(b)If Pressure is constant along with mass then as Temperature increases, Volume also increases.

(c)true , Product of Pressure and volume depends upon temperature thus it also increases with temperature.

(d)Density of gas may or may not increases

As density is \frac{mass}{volume}

volume may increase or decrease as temperature increase .

(e)false

as it clearly stated that quantity of fixed therefore there is no change in gas

8 0
3 years ago
If the speed of a wave is 1500m/sec and its frequency is 200 Hz, what is its wavelength
Ray Of Light [21]

Answer:

The wavelength of wave is 7.5 meter.

Given:

Speed of wave = 1500 \frac{m}{s}

Frequency of wave = 200 Hz

To find:

Wavelength of wave = ?

Formula used:

\lambda = \frac{v}{n}

Where \lambda = wavelength of the wave

v = speed of wave

n = frequency of wave

Solution:

Wavelength of wave is given by,

\lambda = \frac{v}{n}

Where \lambda = wavelength of the wave

v = speed of wave

n = frequency of wave

\lambda = \frac{1500}{200}

\lambda = 7.5 m

The wavelength of wave is 7.5 meter.

4 0
3 years ago
Earth is broken into how may climate zones
Alik [6]
Three climate zones which are polar, temperate, and tropical. hope this helps
8 0
2 years ago
g The international space station has an orbital period of 93 minutes at an altitude (above Earth's surface) of 410 km. A geosyn
krok68 [10]

Answer:

r = 4.21 10⁷ m

Explanation:

Kepler's third law It is an application of Newton's second law where the forces of the gravitational force, obtaining

            T² = (\frac{4\pi }{G M_s} ) r³             (1)

           

in this case the period of the season is

            T₁ = 93 min (60 s / 1 min) = 5580 s

            r₁ = 410 + 6370 = 6780 km

            r₁ = 6.780 10⁶ m

for the satellite

           T₂ = 24 h (3600 s / 1h) = 86 400 s

if we substitute in equation 1

            T² = K r³

            K = T₁²/r₁³

            K = \frac{ 5580^2}{ (6.780 10^6)^2}

            K = 9.99 10⁻¹⁴ s² / m³

we can replace the satellite values

            r³ = T² / K

            r³ = 86400² / 9.99 10⁻¹⁴

            r = ∛(7.4724 10²²)

            r = 4.21 10⁷ m

this distance is from the center of the earth

7 0
2 years ago
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