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LuckyWell [14K]
1 year ago
6

In the Roman soldier model for refraction, what happens to the distance between the rows of each soldier once they enter the str

eam?
A. Not enough info
B. They are closer together
C. They stay the same distance
D. They are further apart
Physics
1 answer:
Anon25 [30]1 year ago
4 0

They pick up speed and move away from the usual.

Using meter sticks, a group of pupils makes a straight line (shoulder to shoulder) and connects to their closest neighbor. Two media are separated in the room by a strip of masking tape. Students can be seen moving normally in one of the media (on one side of the tape). The kids in the other medium (or on the opposite side of the tape) move very slowly and in baby stages. The class moves in the union in a straight line in the direction of the diagonal piece of masking tape. As they get close to the masking tape, the pupils stay in line. Each pupil immediately changes the speed of her or his walk as she or he reaches the tape.

learn more about distance: brainly.com/question/17273444

#SPJ1

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A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
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\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

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\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}

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2 years ago
Cold air holds less water than warm air.<br> True<br> False
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The answer is for your question is :

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True

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2 years ago
A 1200 kg sports car accelerates from 0 m/s to 30 m/s in 10 s. What is the average power of the engine?
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3600N

Explanation:

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ΣF = ma

we need to find 'a' first, using the definition of 'a' we get equation:

a = (Vf-Vo)/Δt

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5 0
2 years ago
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A coin is thrown with a velocity of 0 m/s down a dry well and hits bottom in 1.2s, what’s the depth of the well?
pentagon [3]

Answer:

The well is 7.1 meters deep.

Explanation:

The formula to use here is the distance in a uniformly accelerated motion:

d = \frac{1}{2}at^2+v_0t+d_0

where d stands for distance, t for time, a for acceleration, v0 and d0 for initial velocity and distance, respectively. Since the initial distance and velocity are both zero, we are left with the first term. The coin is in free fall and so it is accelerated by gravity:

d = \frac{1}{2}at^2= \frac{1}{2}gt^2=\frac{1}{2}9.8\frac{m}{s^2}1.2^2s^2=7.1m

The well is 7.1 meters deep.

5 0
3 years ago
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