<h2>
Answer: 56.718 min</h2>
Explanation:
According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.
</em>
In other words, this law states a relation between the orbital period 
of a body (moon, planet, satellite) orbiting a greater body in space with the size 
of its orbit.
This Law is originally expressed as follows:
(1)
Where;
is the Gravitational Constant and its value is 
is the mass of Mars
is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)
If we want to find the period, we have to express equation (1) as written below and substitute all the values:
(2)
(3)
(4)
Finally:
This is the orbital period of a spacecraft in a low orbit near the surface of mars
Answer:
Subcategories: Ice field
Explanation:
Glacier ice is blue because the red (long wavelengths) part of white light is absorbed by ice and the blue (short wavelengths) light is transmitted and scattered. The longer the path light travels in ice, the more blue it appears.
<u>Answer:</u>
Ball will move 92.8125 meter along the cliff in 7.5 seconds.
<u>Explanation:</u>
We have equation of motion , 
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this case initial velocity = 0 m/s, acceleration = 3.3 
, we need to calculate displacement when time = 7.5 seconds.
Substituting
So ball will move 92.8125 meter along the cliff in 7.5 seconds.
Answer: 26 beats in 2 seconds
Explanation:
The number of beats per second = frequency of tuning fork 1 - frequency of tuning fork 2.
Given :
- frequency of tuning fork 1 = 500Hz
- frequency of tuning fork 2 = 487Hz
Thus,
Beats per second = 500 - 487
= 13 beats per second
Therefore in two(2) seconds, you will have 2 x 13 = 26 seconds.
