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Alenkasestr [34]
3 years ago
5

Which of the following lists stars in order of increasing size?

Chemistry
2 answers:
Nady [450]3 years ago
7 0

The answer is b i just did it.

Citrus2011 [14]3 years ago
3 0
B. Or D. Im confused they both make sence
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3. What determines the mass number of an element?<br> The mumhor of nrotons
ArbitrLikvidat [17]

Answer: The number of protons and the number of neutrons determine an element's mass number.

Explanation:

5 0
3 years ago
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Another carbon isotope has six protons and seven neutrons in its nucleus. What do you think this carbon isotope is called?
insens350 [35]

Answer:

Carbon - 13

Explanation:

For most of the elements other than that of hydrogen, the isotopes are named for the mass number.

Example : Carbon atoms with 6 neutrons have mass number of 12 ( as 6\ protons +6\ neutrons=12 ), so they are known as carbon-12.

Given that:

Protons = 6

Neutrons = 7

Mass = 6 + 7 = 13

So the name is Carbon - 13 . The symbol is ^{13}_{6}C

8 0
3 years ago
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Two glucose molecules can combine to form a disaccharide molecule and what molecule
elena-14-01-66 [18.8K]
And a water molecule, this is called a dehydration synthesis. when 2 molecule combine, a water molecule leave.
5 0
3 years ago
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises
OLga [1]

Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

Mass of gold =.?

Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

Note: 1 mL is equivalent to 1 cm³

Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

Therefore, the mass of the gold pebble is 142.82 g

6 0
3 years ago
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