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nikklg [1K]
3 years ago
5

The diagram shows heat energy being transferred as hot water rises to the top of the pot and cool water sinks to the bottom.

Chemistry
1 answer:
Orlov [11]3 years ago
7 0
I think it would be insulation
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Skeleton equation for
Verizon [17]

Answer:

Magnesium oxide = MgO

Iron = Fe

Iron (III) Oxide = Fe₂O₃

Magnesium = Mg

Skeleton equation = MgO + Fe ⇒ Fe₂O₃ + Mg

3 0
3 years ago
Which components of an endothermic reaction have a higher heat content?
trasher [3.6K]
The answer is B. products
5 0
3 years ago
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Why compounds with weak molecular forces are usually gases.
mihalych1998 [28]

Answer:

Intermolecular forces are much weaker than the strong covalent bonds within the molecules. ... Very little energy is needed to overcome the intermolecular forces, so simple molecular substances usually have low melting and boiling points. They are often liquids or gases at room temperature

8 0
2 years ago
What is the solubility of NH4Cl at 50°C?
astra-53 [7]

The correct answer is E. 50 grams

The solubility of Ammonium Chloride has an increasing trend as the temperature increases. Experiments show that the solubility at 323K is approximately 50.4 grams per 100 grams o water thus this value is close to choice D, 50 grams

8 0
3 years ago
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How many grams of propane are in 20 pounds of propane? Use the conversion 1 lb = 454 g. (Express your answers for the next three
Dima020 [189]

Answer:

a. =9.1x10^3gC_3H_8

b. 2.1x10^2molC_3H_8

c. Q=-4.6x10^5kJ

Explanation:

Hello,

a. By applying the given information, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8} =9.1x10^3gC_3H_8

b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8}*\frac{1molC_3H_8}{44gC_3H_8} =2.1x10^2molC_3H_8

c. Here, the propane's combustion chemical reaction is stated:

C_3H_8+5O_2-->3CO_2+4H_2O

This enthalpy of reaction is computed via:

ΔrH=(3*-393.5kJ/mol)+(4*241kJ/mol)-(-104.7kJ/mol)=-2043kJ/mol

Finally, since it is done for 20 lb of propane (2.1x10^2molC_3H_8), the obtainable energy is:

Q=-2043kJ/mol*2.1x10^2molC_3H_8\\Q=-4.6x10^5kJ

Best regards.

4 0
3 years ago
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