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Vinil7 [7]
3 years ago
11

How to find the concentration and equilibrium and the pH for a acid solution when you have 0.20M and the Ka

Chemistry
1 answer:
klio [65]3 years ago
3 0

you use the chem calculations.

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A 100. ml portion of 0.250 m calcium nitrate solution is mixed with 400. ml of 0.100 m nitric acid solution. what is the final c
pshichka [43]
<span>Answer: Moles Ca(NO3)2 = 100 x 0.250 / 1000 = 0.025 Ca(NO3)2 >> Ca2+ + 2NO3- Moles NO3- = 2 x 0.025 = 0.05 Moles HNO3 = 400 x 0.100 / 1000 = 0.04 Total moles = 0.05 + 0.04 = 0.09 Total volume = 500 ml = 0.500 L M = 0.09 / 0.500 = 0.18</span>
6 0
4 years ago
What happens when carbon dioxide is passed through lime water for a long time? write with equation​
Vlada [557]

Answer:

when CO2 gas is passed through lime water it turns milky due to the formation of calcium carbonate which formula is CaCO3.

Ca(OH)2+ CO2------ CaCO3

when excess of carbon dioxide is passed through calcium carbonate calcium hydrogen carbonate is formed and solution become colourless.

CaCO3+CO2------ Ca(HCO3)

5 0
3 years ago
How are stars and comets different?
ehidna [41]
The answer is letter C.

Because we classify something as a star when it is: a large ball of gas that undergoes nuclear fusion. Given this definition, a comet is not a star. A comet is a ball of ice and dirt hurtling through space, it shines only because it reflects ligh
3 0
2 years ago
What is true of a basic solution at room temperature? it has a ph value below 7. it has a greater concentration of hydroxide com
slega [8]
The true statement about basic solution at room temperature is that it has a greater concentration of hydroxide compared to hydronium ions.
Basic solutions have always pH greater than 7.
Basic solutions have bitter and caustic taste.
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7 0
3 years ago
1. How much energy (in KJ) is required to convert 50.0g of ice at – 30 ˚C to<br> steam at130˚C.
Vitek1552 [10]

Answer:

How much heat energy required to convert following?

How much heat energy, in kilojoules, is required to convert 47.0 g of ice at -18.0 C to water at 25.0 C ?

Specific Heat of Ice - 2.09 j/g * c

This is how I did it and the answer is wrong...Please check and correct me

Q = m * Cice * Change in Temp

Q = (47.0 g)(2.09 J/g*c)(43) = 4222.6 J * 0.001 kj / j = 4.22 kj

4 0
3 years ago
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