88 Grams because the principal of conservation of mass states total mass in equals total out so 200 in 122+88=200 out
Matter is discontinuous, and it is made of tiny particles called atoms
Explanation:
Matter is not a continuous structure, but it consists of tiny particles called atoms.
An atom consists of three types of particles:
- Proton: the proton is in the nucleus of the atom. it has a positive electric charge of
(also called fundamental charge). Its mass is
.
- Neutron: the neutron is also in the nucleus of the atom, but it has no electric charge. Its mass is similar to the mass of the proton (slightly heavier). Neutrons and protons are held together in the nucleus through the strong nuclear force.
- Electron: electrons are found in a "cloud" outside the nucleus. Electron has negative electric charge equal to
. Its mass is much approximately 1800 times smaller than that of the proton, so it is considered as negligible.
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Answer:
<h3>The answer is 1000 g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of object = 50 mL
density = 20 g/mL
We have
mass = 20 × 50
We have the final answer as
<h3>1000 g</h3>
Hope this helps you
The grams of potassium chlorate that are required to produce 160 g of oxygen is 408.29 grams
<u><em>calculation</em></u>
2 KClO₃→ 2 KCl + 3O₂
Step 1: find the moles of O₂
moles = mass÷ molar mass
from periodic table the molar mass of O₂ = 16 x2 = 32 g/mol
moles = 160 g÷ 32 g/mol = 5 moles
Step2 : use the mole ratio to determine the moles of KClO₃
from equation given KClO₃ : O₂ is 2:3
therefore the v moles of KClO₃ = 5 moles x 2/3 = 3.333 moles
Step 3: find the mass of KClO₃
mass= moles x molar mass
from periodic table the molar mass of KClO₃
= 39 + 35.5 + (16 x3) =122.5 g/mol
mass = 3.333 moles x 122.5 g/mol =408.29 grams
The mass of iron block is 500 g. The amount of energy required to melt the iron block needs to be calculated. Melting means conversion of solid to liquid thus, heat of fusion is used which is 247 J/g.
From heat of fusion, 247 J of energy is released by melting 1 g of iron block. Thus, the amount of heat released by melting 500 g of iron rod will be:
H= 247 J/g× 500 g=1.23×10^{5}
Hence, option B is correct.