The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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One of the most poplar examples of commensalism is the relationship between cattle egrets and livestock. The cattle egret is a common species of heron that is found in most regions of the world, and is mostly seen moving along with herds of cattle. This bird moves about in pastures, and follows livestock such as cattle and horses.
This is totally false, the combination of the two could result in overdose or possibly death.
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It is symbiosis, but also called a commensalism relationship because the remora is getting its food and the shark has no benefit.
