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3 years ago

7

A solid cube of side 18 cm is cut into 8 cubes of equal volume what will be the side of the new cube ? Also find the ratio betwe

en thier surface area

2 answers:

maks197457 [2]3 years ago

5 0

The volume of the original cube = 18^3 = 5,832 cubic cm

5,832 / 8 cubes = 729 cubic cm.

Side length = Cubicroot729 = 9

The side length is 9 cm

ipn [44]3 years ago

5 0

Answer:

The side length is 9 cm

Step-by-step explanation:

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What is 30 divide by 4?

Sedaia [141]

Answer:

30 ÷ 4 = <em>7.5</em>

Step-by-step explanation:

This means that:

7.5 fits into 30 4 times

Example:

7.5 + 7.5 + 7.5 + 7.5

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7 0

3 years ago

Simplify the polynomial by combining like terms

Veseljchak [2.6K]

Answer:

22 x^2

Step-by-step explanation:

Simplify the following:

11 x^2 + 11 x^2

Hint: | Add like terms in 11 x^2 + 11 x^2.

11 x^2 + 11 x^2 = 22 x^2:

Answer: 22 x^2

none of your answers are correct.

8 0

2 years ago

I don't know how to do things like this :(

Fofino [41]

Answer:

Step-by-step explanation:

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3 0

2 years ago

Read 2 more answers

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

$\frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)$

$\frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)$

Simplify the equation.

$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )$

Therefore, this is the 2nd derivative of the function f(x).

We can say that: $f''(x)=36x^2+4$

6 0

2 years ago

Read 2 more answers

Which expression is equivalent to:1/m6

Valentin [98]

Answer:

A

Step-by-step explanation:

6 is a power. So both C and D are wrong because 6 is being treated as an ordinary integer.

So the answer must be either A or B.

B is not correct because to move an expression from the denominator to the numerator changes the sign in the base (which is m in this question).

A is correct. the power is changed from 6 in the denominator to -6 in the numerator. m is shifted to the numerator as well.

8 0

2 years ago