All categories

3 years ago

The box-and-whisker plot below shows the age distribution of people at a family reunion.

Mathematics

2 answers:

Elden [556K]3 years ago

8 0

Answer:

C. The interval of the stem and leaf plot is not consistent.

Step-by-step explanation:

Nesterboy [21]3 years ago

4 0

Answer:

C. The interval of the stem and leaf plot is not consistent.

Step-by-step explanation:

The stem and leaf plot appears at first glance to be accurate. However, 5 is skipped altogether in the stems; this makes the plot look symmetric instead of skewed.

You might be interested in

9.92749, √101, 0.99853, 10π greatest to least

Fudgin [204]

Using a calculator, determine the value of √101 to four or five decimal places. Do the same with 10π. We get { 9.92749, 10.0500, 0.99853, 31.4159}.

Arranging these in descending order, we get {10π, √101, 9.92749, 0.99853}.

8 0

3 years ago

Round 4.89 to the nearest tenth

MA_775_DIABLO [31]

4.9 is answer you are looking for.

7 0

4 years ago

Read 2 more answers

I need help with this question ASAP

zubka84 [21]

Answer:

A, D, and I think E

I hope this helps :)

8 0

3 years ago

Suppose that 7 in every 10 auto accidents involve a single vehicle. If 15 auto accidents are randomly selected, compute the prob

kobusy [5.1K]

Answer:

$\mathbf{P(X \le 4 ) \simeq 0.0006722}$

Step-by-step explanation:

From the information given:

p = x/n

p = 7/10

p = 0.7

sample size n = 15

Suppose X be the number of accidents involved by a single-vehicle.

Then;

$X \sim Binom (15,0.7)$

Thus, the required probability that at most 4 involve in a single-vehicle is

$P(X\le 4) \\ \\P(X \le 4) = P(X = 0) + P(X =1 ) + ... + P(X = 4)$

$P(X \le 4 ) = (^{15}_0) *0.7^0 *0.3^{15-0} + (^{15}_1) *0.7^1 *0.3^{15-1} + (^{15}_2) *0.7^2 *0.3^{15-2} + (^{15}_3) *0.7^3 *0.3^{15-3} + (^{15}_4) *0.7^4 *0.3^{15-4}$

$P(X \le 4 ) = (\dfrac{15!}{0!(15-0)!}) *0.7^0 *0.3^{15-0} + (\dfrac{15!}{1!(15-1)!}) *0.7^1 *0.3^{15-1} + (\dfrac{15!}{2!(15-2)!}) *0.7^2 *0.3^{15-2} + (\dfrac{15!}{3!(15-3)!}) *0.7^3 *0.3^{15-3} + (\dfrac{15!}{4!(15-4)!}) *0.7^4 *0.3^{15-4}$

$P(X \le 4 ) =1.4348907 \times 10^{-8} +5.02211745 \times 10^{-7} + 8.20279183 \times 10^{-6} + 8.29393397 \times 10^{-5} + 5.80575378 \times 10^{-4}$

$P(X \le 4 ) =6.7223407 \times 10^{-4}$

$\mathbf{P(X \le 4 ) \simeq 0.0006722}$

3 0

3 years ago

What expression is equivalent to 2x+3y-x-(8+1)

Paha777 [63]

Answer:

Step-by-step explanation:

2x + 3y - x - 9

x + 3y - 9

3 0

3 years ago