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Mariana [72]
3 years ago
11

Can physics measure the work a porter does? What do you need to know to measure a porters work? What produces work, and how is p

ower different from work?
Physics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

No

Explanation:

According to physics, the work done by porter is zero but in reality porter gets tired as muscular energy is being used up.

In physics, work is the dot product of force and displacement. when the porter moves with the luggage, the weight act downwards while the porter moves forward. The angle between force and displacement is 90°. Thus, work done by the porter is zero.

The muscles are doing work in this case which is not calculated in physics.

Power is the rate of energy consumed during the work.

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Find the area of the part of the plane 5x 3y z = 15 that lies in the first octant.
Lunna [17]

This part of the plane lies above a triangle with boundaries x=0 and y=0 along the coordinate axes, as well as the line

z=0 \implies 5x + 3y = 15 \implies y = \dfrac{15 - 5x}3

When y=0, we have 15-5x=0\implies x=3. So this triangle is the set

T = \left\{(x,y)\in\Bbb R^2 ~:~ 0\le x\le3 \text{ and } 0\le y\le\dfrac{15-5x}3\right\}

Also, when x=0, we have y=\frac{15}3=5. So the triangle has length 3 and width 5, hence area 1/2•3•5 = 15/2.

Let z=f(x,y) = 15 - 5x - 3y. Then the area of the plane over T is

\displaystyle \iint_T dA = \iint_T \sqrt{1 + \left(\frac{\partial f}{\partial x}\right)^2 + \left(\frac{\partial f}{\partial y}\right)^2} \, dx \, dy

We have

\dfrac{\partial f}{\partial x} = -5 \implies \left(\dfrac{\partial f}{\partial x}\right)^2 = 25

\dfrac{\partial f}{\partial y} = -3 \implies \left(\dfrac{\partial f}{\partial y}\right)^2 = 9

\implies\displaystyle \iint_T dA = \sqrt{35} \iint_T dx\,dy = \boxed{\frac{15\sqrt{35}}2}

since the integral

\displaystyle \iint_TdA

is exactly the area of T, 15/2.

8 0
2 years ago
Yoon Ki investigates electromagnetic induction by moving a bar magnet into a coil of wire. His experimental setup is shown.
Karolina [17]

A change that would most improve his results would be; D) Connecting the galvanometer to the coil

4 0
3 years ago
Read 2 more answers
A toroid having a square cross section, 5.49 cm on a side, and an inner radius of 18.1 cm has 450 turns and carries a current of
joja [24]

Answer:

(a) 4.27 x 10^-4 Telsa

(b) 3.28 x 10^-4 Telsa

Explanation:

side of square, a = 5.49 cm

inner radius, r = 18.1 cm = 0.181 m

number of turns,N = 450

current, i = 0.859 A

(a)

The magnetic field due to a solenoid due to inner radius is

B = \frac{\mu_{0}Ni}{2\pi r_{inner}}

B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.181}

B = 4.27 x 10^-4 Telsa

(b)

The outer radius is R = 18.1 + 5.49 = 23.59 cm = 0.236 m

The magnetic field due to the outer radius is

B = \frac{\mu_{0}Ni}{2\pi r_{outer}}

B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.236}

B = 3.28 x 10^-4 Tesla

7 0
4 years ago
A car starting from rest (i.e. initial velocity = 0.0 m/s), moves in the positive X-direction with a constant average accelerati
olga_2 [115]

Answer:

Final speed of the car, v = 24.49 m/s

Explanation:

It is given that,

Initial velocity of the car, u = 0

Acceleration, a=3.1\ m/s^2

Time taken, t = 7.9 s

We need to find the final velocity of the car. Let it is given by v. It can be calculated using first equation of motion as :

v=u+at

v=0+3.1\times 7.9

v = 24.49 m/s

So, the final speed of the car is 24.49 m/s. Hence, this is the required solution.

8 0
3 years ago
Does the earths magnetic field change with time?
ZanzabumX [31]

Answer:

As per the fossil fuel records, magnetic field reversal does not impact living beings. It will take almost a century for the poles to complete the shift. Meanwhile, the earth is left with almost zero magnetic field.

6 0
3 years ago
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