What is refraction of light?
2 answers:
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Answer:
534 ft
Explanation:
given,
speed of the vehicle = 60 mph
1 mph = 0.447 m/s
60 mph = 60 x 0.447 = 26.82 m/s
stopping distance = ?
Stopping distance of the car is equal to the distance traveled in the reaction time and the braking distance.
Reaction time of a common person = 1.5 s
taking coefficient of friction of the road = 0.3
using equation of stopping sight distance
S.D = RD + BD
RD is Reaction distance
RD = v t_r
RD = 26.82 x 1.5
RD = 40.23 m
BD is the braking distance
BD = 122.33 m
Stopping sight distance
SD = 40.23 + 122.33
SD = 162.56 m
1 m = 3.28 ft
162.56 m = 162.56 x 3.28
= 533.20 ft ≈ 534 ft
hence, the stopping distance will be equal to 534 ft
Answer:
19.4 seconds
Explanation:
We have:
m: mass of the car = 1500 kg
v₀: is the initial speed = 19 m/s
: is the final speed = 0 (it stops)
: is the coefficient of kinetic friction = 0.100
First, we need to find the acceleration by using the second Newton's law:
Solving for a:
Now we can find the time until it stops:
Solving for t:
Therefore, the time until it stops is 19.4 seconds.
I hope it helps you!