Electromagnetic radiation in order of increasing (lowest to highest) frequency is Radio waves < Green visible light < UV radiation.
<h3>What is Frequency?</h3>
This is defined as the rate at which something occurs or is repeated over a particular period of time. The unit of frequency is referred to as Hertz.
Electromagnetic radiations with increasing frequency can be seen below:
Radio waves, microwaves, infrared waves, visible light, ultraviolet radiations, X rays, γ rays.
Read more about Frequency here brainly.com/question/254161
W = ∫ (x from 0.1 to +oo) F dx
= ∫ (x from 0.1 to +oo) A e^(-kx) dx
= A/k x [ - e^(-kx) ](between 0.1 and +oo)
= A/k x [ 0 + e^(-k * 0.1) ]
<span>
= A/k x e^(-k/10) </span>
A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North.
I need help to I have a big test and I need help so bad
