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Luba_88 [7]
3 years ago
12

The triangle shown in the graph is transformed by matrix R. Plot the resulting triangle.

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

I cant Im sorry

Step-by-step explanation:

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5a+c=-8a, for a how do you solve this problem?
BaLLatris [955]
The answers is A= C/-13

C= 13A
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13. Find the range of the function on the graph<br> below.
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Range is ] -20 , -10 [

both points are disclude according to the empty circle

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1 year ago
What is the perimeter of the figure? <br><br> A. 144 cm <br> B. 76 cm <br> C. 74 cm <br> D. 45 cm
tatiyna
76 cm would be your answer, so B.
8 0
3 years ago
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ALGEBRA<br> EQUATION<br> PLEASE HELP ASAP<br><br> -3=12y-5(2y-7)
Dovator [93]

Simplify:

−3=12y−5(2y−7)

−3=12y+(−5)(2y)+(−5)(−7)(Distribute)

−3=12y+−10y+35

−3=(12y+−10y)+(35)(Combine Like Terms)

−3=2y+35

Flip the equation.

2y+35=−3

Subtract 35 from both sides.

2y+35−35=−3−35

2y=−38

Divide both sides by 2.

2y/2=−38/2

y=−19


3 0
3 years ago
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What is the vertex of the absolute value function defined by ƒ(x) = |x + 2| + 4?
Marrrta [24]

Answer:

C. (-2,4)

Step-by-step explanation:

We have been given a function f(x)=|x+2|+4 and we are asked to find the vertex of our absolute value function.

The rules for the translation of a function are as follows:  

f|x-h|=\text{Graph shifted to right by h units}

f|x+h|=\text{ Graph shifted to left by h units}

f|x|+h=\text{ Graph shifted upward by h units}

f|x|-h=\text{ Graph shifted down by h units}

Upon comparing our absolute function with above transformations we can see that our function is shifted to two units right of the origin(0,0) so x coordinate of our absolute function will be -2.

Our function is shifted upward from origin by 4 units, therefore, y-coordinate of our absolute value function will be 4.

f(x)=|x--2|+4

Therefore, the vertex of our absolute value function will be on point (-2,4) and option C is the correct choice.

4 0
3 years ago
Read 2 more answers
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