Question

Please help me ASAP?!!

Answer 1

Answer:

(0,-5) and (-4,3)

Step-by-step explanation:

The given equations are

$\left \{ {{x^2+y^2=25} \atop {2x+y=-5}} \right.$

Make y the subject in the second equation;

$y=-2x-5$

Substitute into the first equation;

$x^2+(-2x-5)^2=25$

Expand:

$x^2+4x^2+20x+25=25$

$x^2+4x^2+20x+25-25=0$

$5x^2+20x=0$

$5x(x+4)=0$

$\Rightarrow x=0,x=-4$

When x=0,

$y=-2(0)-5=-5$

This gives; (0,-5)

When x=-4

$y=-2(-4)-5=3$

This gives (-4,3)

Answer 2

the answer 05 and 4 13