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WITCHER [35]
3 years ago
12

Please help me ASAP?!!

Mathematics
2 answers:
Blababa [14]3 years ago
7 0

Answer:

(0,-5) and (-4,3)

Step-by-step explanation:

The given equations are

\left \{ {{x^2+y^2=25} \atop {2x+y=-5}} \right.

Make y the subject in the second equation;

y=-2x-5

Substitute into the first equation;

x^2+(-2x-5)^2=25

Expand:

x^2+4x^2+20x+25=25

x^2+4x^2+20x+25-25=0

5x^2+20x=0

5x(x+4)=0

\Rightarrow x=0,x=-4

When x=0,

y=-2(0)-5=-5

This gives; (0,-5)

When x=-4

y=-2(-4)-5=3

This gives (-4,3)

stich3 [128]3 years ago
3 0

the answer 05 and 4 13

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