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3 years ago

I do not understand how to solve this. Please can someone explain in a way i can understand.

Mathematics

1 answer:

Hoochie [10]3 years ago

7 0

This π (pi) means 22/7 (pi).

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SA = 2tr2 + 2trh

julsineya [31]

Given:

Radius of the cylinder = 5 in

Height of the cylinder = 30 in.

To find:

The surface area of the cylinder.

Solution:

The surface area of the cylinder is:

$SA=2\pi r^2+2\pi rh$

Where, r is the radius and h is the height of the cylinder.

Putting $r=5,h=30,\pi=3.14$ in the above formula, we get

$SA=2(3.14)(5)^2+2(3.14)(5)(30)$

$SA=2(3.14)(25)+942$

$SA=157+942$

$SA=1099
$

Therefore, the surface area of the cylinder is 1099 square inches.

6 0

2 years ago

Number 3 please need help

kirza4 [7]

Im pretty sure it would be 4

4 0

3 years ago

Can someone help please and thank you

denis-greek [22]

Try making a grid like this. Apologies for the terrible drawing and handwriting. It represents all possible results of rolling two dice and summing their values. The blue column and yellow row represent the values of each die, and the green numbers reptesent their sums.
First, you can see that there are 36 possible values. Second, it's easy to see how many results are greater than 9, since they're all in one corner. And last, you can see just how many are even and how many are odd. Remember to reduce your fractions in the end.

8 0

3 years ago

Any campground rides bicycles by the hour the Total cost why to rent a bicycle including deposit is presented by the function Y

alisha [4.7K]

The answer is 6+2 jaja

7 0

2 years ago

The article on the next page from the San Francisco Chronicle, January 27, 1996, describes very serious problems of subsidence,

Mekhanik [1.2K]

Answer:

246.3%

the complete question is found in the attached document

Step-by-step explanation:

1st step:

using 1936 data,

w1= 356% = 3.56(356/100) , H= 79 feet

specific gravity = 2.65

Sₓ= 100%= 1

initial void ratio(e₀)= (w1 x specific gravity)/Sₓ

=3.56 x 2.65/1 = 9.434

2nd step

using 1996 data

ΔH= 22ft

ΔH/H = Δe/(1 + e₀)

22/79 = Δe/(1+9.434)

0.278=Δe/10.434

Δe= 0.278 x 10.434

Δe= 2.905

Δe= e₀ - eₓ

eₓ= e₀-Δe

eₓ= 9.434 - 2.905

eₓ= 6.529

3rd step

calculating water content in 1996

eₓ =6.529, specific gravity= 2.65, Sₓ= 100%

W2 X 2.65 = 1 x 6.529

w2 = 6.529/2.65 = 2.463 = 246.3%

6 0

3 years ago