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Dovator [93]
3 years ago
15

Find the length of the third side. If necessary, round to the nearest tenth.

Mathematics
2 answers:
Shtirlitz [24]3 years ago
5 0
240 bc you need to mulitpy it and ye
34kurt3 years ago
5 0
240 I think sorry if I’m wrong
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In ΔMNO, m∠M = 57° and m∠N = 75°. Which list has the sides of ΔMNO in order from shortest to longest?
gulaghasi [49]

Answer:

B. MN, NO, OM

Step-by-step explanation:

Recall: In any triangle, the sides and the angles are related in the following way:

*The largest angle and the longest side are opposite each other

*The medium angle and the mid-sized side are opposite each other

*The smallest angle and the shortest side are opposite each other

In ∆MNO, we are given that

m<M = 57° which is opposite to side NO

m<N = 75° which is opposite to side OM

m<O = 180° - (75° + 57°) (sum of triangle)

m<O = 48° which is opposite to side MN

Therefore, we can write the order of shortest to longest side in relation to their opposite angles as follows:

MN, NO, OM

7 0
3 years ago
Find the upper quartile of this data set: 593, 588, 540, 434, 420, 398, 390, 375
ratelena [41]
The answer is D. 564
When you put all the numbers in order from least to greatest and find the median which is between 420 and 434, you can then find your upper quartile which would be between 540 and 588 making it D
4 0
3 years ago
(A)using geometry vocabulary, describe a sequence of transformations that maps figure P (-1,2)(-1,4) (-4,2) (-4,4) onto figure Q
andrey2020 [161]

Before we proceed on determining the transformation happening on this problem, it's better to see first the location of the figure by drawing it in a cartesian coordinate plane. We have

If we observe the figures and the coordinates of the plot, we can see that there is a difference of 1 on the x coordinates of P and y coordinates of Q. Therefore, the first transformation that we consider here is the movement of figure P by 1 unit to the left. We have

\begin{gathered} P_1=(-1-1,2_{})=(-2,2) \\ P_2=(-1-1,4)=(-2,4) \\ P_3=(-4-1,2)=(-5,2) \\ P_4=(-4-1,4)=(-5,4) \end{gathered}

This transformation changes the location of figure P into

The next transformation will be the rotation of the red dotted figure on the figure above by 90 degrees counterclockwise. With this transformation, the coordinates will transform as

P_{ccw,90}=(-y,x)

Hence, for the rotation, we have the new coordinates.

\begin{gathered} P_1^{\prime}=(-2,-2) \\ P_2^{\prime}=(-4,-2) \\ P_3^{\prime}=(-2,-5) \\ P_4^{\prime}=(-4,-5) \end{gathered}

The transformed image, which is represented as NMPO, will now be at

For the last transformation, we will be reflecting the figure NMPO over the <em>y</em> axis. This changes the coordinates as

P_{\text{rotation,y}-\text{axis}}=(-x,y)

We now have the new coordinates:

\begin{gathered} P^{\doubleprime}_1=(2,-2)=Q_1_{}_{} \\ P_2^{\doubleprime}=(4,-2)=Q_3 \\ P_3^{\doubleprime}=(2,-5)=Q_2 \\ P_4^{\doubleprime}_{}=(4,-5)=Q_4_{} \end{gathered}

As you can see, they have the same coordinates as figure Q.

The mapping rules for the sequence described above are as follows:

First transformation (moving one unit to the left (x-1,y))

\begin{gathered} P_1(-1,2)\rightarrow P_1(-1-1,2)\rightarrow P_1(-2,2) \\ P_2(-1,4)\rightarrow P_1(-1-1,4)\rightarrow P_2(-2,4) \\ P_3(-4,2)\rightarrow P_1(-4-1,2)\rightarrow P_3(-5,2) \\ P_4(-4,4)\rightarrow P_1(-4-1,4)\rightarrow P_4(-5,4) \end{gathered}

Second transformation (rotation counter clockwise (-y,x))

\begin{gathered} P_1(-2,2)\rightarrow P^{\prime}_1(-2,-2)_{} \\ P_2(-2,4)\rightarrow P^{\prime}_2(-4,-2) \\ P_3(-5,2)\rightarrow P^{\prime}_3(-2,-5)_{} \\ P_4(-5,4)\rightarrow P^{\prime}_4(-4,-5)_{} \end{gathered}

Third Transformation (reflection over y-axis (-x,y))

\begin{gathered} P^{\prime}_1(-2,-2)\rightarrow P^{\doubleprime}_1(-(-2),-2)\rightarrow P^{\doubleprime}_1=(2,-2)=Q_1 \\ P^{\prime}_2(-4,-2)\rightarrow P^{\doubleprime}_1(-(-4),-2)\rightarrow P^{\doubleprime}_1=(4,-2)=Q_3 \\ P^{\prime}_3(-2,-5)\rightarrow P^{\doubleprime}_1(-(-2),-5)\rightarrow P^{\doubleprime}_1=(2,-5)=Q_2 \\ P^{\prime}_4(-4,-5)\rightarrow P^{\doubleprime}_1(-(-4),-5)\rightarrow P^{\doubleprime}_1=(4,-5)=Q_4 \end{gathered}

7 0
1 year ago
The equation i need help with in math is x-7=-13, i need a step by step anwser
vladimir2022 [97]

If x - 7 = -13, we need to get x by itself to solve this equation. To get x by itself, we can add 7 to each side (that way x will be by itself, and only on one side of the equation).


x - 7 + 7 = -13 + 7


We can add 7 to each side without changing the quantity because we do it to BOTH sides.


x = -13 + 7


Since -13 + 7 is -6,


x = -6

6 0
3 years ago
12X-7X(1-9X)=-3+9X(7X-1)
Georgia [21]
What are you solving for? X?
5 0
3 years ago
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