Question

the perimeter of a rectangle is 132 m. the length is 2 meters more than 3 times the width. find the dimensions of the rectangle

Answer 1

2l + 2w = 132
l = 3w + 2

2(3w+2)+2w=132
6w + 4 + 2w = 132
8w + 4 = 132
8w = 128
w = 16

l = 3(16) + 2
l = 48 + 2
l = 50

2(50) + 2(16) __ 132
100 + 32 = 132