2 years ago

A: Describe how to find the range of the data set. b: Find the range.

Mathematics

1 answer:

Vesnalui [34]2 years ago

6 0

Answer:

b. 5,2

a. Deduct the lowest from the highest quantity, so you would do this:

$-12,3 + 17,5$

I am joyous to assist you anytime.

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Does 2x+4=3x+1/2 have one solution or more or none?

Contact [7]

Answer:

one solution the solution being ×=7/2

Step-by-step explanation:

one solution

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2 years ago

WRITE AN EQUATION FOR EACH OF THESE AND SOLVE IT TO FIND THE VALUE OF THE UNKNOWN NUMBER:

castortr0y [4]

a) a *5+5= 20

5a + 5 = 20

5a = 20 - 5

5a = 15

a = 15/5

a = 3

b) b/5 - 5 = 4

b/5 = 4 + 5

b/5 = 9

b =9*5

b = 45

8 0

2 years ago

Read 2 more answers

Consider the parametric curve:

11Alexandr11 [23.1K]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}=\dfrac{4\sec t\tan t}{3\sec^2t}=\dfrac43\sin t$

When $t=\pi$ , we have

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{t=\pi}=\dfrac43\sin\pi=0$

7 0

2 years ago

PLEASE HELP :(((<br><br><br> When a number x is multiplied by 4 and the result is 2/5

ioda

I don't understand the question

4 0

2 years ago

What is the completely factored form of d4 -8d2 + 16

irinina [24]

According to Vieta's Formulas, if $x_1,x_2$ are solutions of a given quadratic equation:

$ax^2+bx+c=0$

Then:

$a(x-x_1)(x-x_2)$ is the completely factored form of $ax^2+bx+c$ .

If choose $x=d^2$ , then:

$\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm \sqrt{64-64} }{2}=4$

So, according to Vieta's formula, we can get:

$x^2-8x+16=(x-4)(x-4)= (x-4)^2$

But $x=d^2$ :

$d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2$

8 0

2 years ago