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Alika [10]
3 years ago
5

Please help :) what is the average rate of change for the interval from x=3 to x=5 ?

Mathematics
2 answers:
qwelly [4]3 years ago
7 0

Answer:

c, 49

Step-by-step explanation:

y2-y1/x2-x1

125-27/5-3

98/2

49

Nataly [62]3 years ago
7 0

\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 0&1\\ 1&3\\ 2&9\\ \underline{3}&\underline{27}\\ 4&64\\ \underline{5}&\underline{125}\\ 6&216 \\ \cline{1-2} \end{array}~\hfill \begin{array}{llll} slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \begin{cases} x_1=3\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(3)}{5-3}\implies \cfrac{125-27}{2}\implies \cfrac{98}{2}\implies 49

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Sarah bought a binder for $7.25 and six folders that totaled $9.05 how much did each folder cost
creativ13 [48]

Answer:

Each binder costs 30 cents or $0.30

Step-by-step explanation:

If Sarah's total was $9.05 and the binder costs 7.25 then in order to find the price of the folders you must subtract the cost of the binder (7.25) from the total (9.05) which leaves $1.80 as the amount she paid in total for 6 folders. Next, to find the amount spent per folder divide 1.80 by the number of folders which is 6 and your final answer should be 0.30.

9.25= 7.25+6x (next subtract 7.25 on both sides)

1.80=6x (next divide by six on both sides)

0.30=x

4 0
3 years ago
Read 2 more answers
CONSUMER MATH!!
Alexxx [7]

Answer:

$10.52

Step-by-step explanation:

(1137.45 x 14.7%) / 12 - (1137.45 x 3.6%) /12 = 10.52

6 0
3 years ago
QUESTION
Lorico [155]
1. For this item we just refer to the prompt to know the conjectures of Ernest and Denise. According to Ernest, they should swim 1 kilometer on the first week then add 0.25km every week while Denise believes that they should swim 1 kilometer on the first week then add 0.5km every week.

2. Yes, these distances make an arithmetic sequence. It's because an arithmetic sequence is defined as a group of increasing or decreasing numbers where the difference between any two consecutive numbers is constant. This just means that every number has the same interval. In the case of their schedule, this is true.

3. For this item we just follow the descriptions of Ernest's and Denise's schedule in item number 1. For Ernest, we just keep adding 0.25 from 1 kilometer until we added it thrice. For Denise, we also keep adding a number thrice but this time it's 0.5 instead of 0.25.

Ernest's Schedule: 1, 1.25, 1.5, 1.75
Denise's Schedule: 1, 1.5, 2, 2.5

4. Here we are asked to determine a formula that will describe the schedules of Ernest and Denise. In the given formula a_{n}= a_{n-1}+d, a_{n} refers to the next term in the sequence, a_{n-1} refers to the previous term, while d refers to the common difference. In the recursive formula all we need is to insert the value of d to the equations.

Ernest: a_{n}= a_{n-1}+0.25
Denise: a_{n}= a_{n-1}+0.5

5. For this item we basically do the same thing but this time we are given another formula. Our formula is in the form a_{n}= a_{1}+(n-1)d where a_{n} is still the nth term of the sequence, a_{1} is the very first time, n is the number of terms, and d is the common difference. 

Ernest: a_{n}= 1.0+0.25(n-1)
Denise: a_{n}= 1.0+0.5(n-1)

6. In this item we will just basically substitute numbers to one of the equations that we've set up in item #5. For this we need Ernest's explicit formula first. To know how far they will be swimming on week 10, the number of elements (n) must be 10.

a_{10}= 1.0+0.25(10-1)
a_{10}= 1.0+0.25(9)
a_{10}= 1.0+2.25
a_{10}= 3.25

7. Here, we just do the same thing as item #6 but this time we will consider Denise's explicit formula. Since we are also asked how far the students will be swimming on week 10, the number of elements would also be 10 and this would also be our value for n.

a_{10}= 1.0+0.5(10-1)
a_{10}= 1.0+0.5(9)
a_{10}= 1.0+4.5
a_{10}= 5.5

8. The answer for this question is obvious. You would just need to look at the 10th element in Ernest's and Denise's sequences and tell whose schedule had more than or equal to 5 as an answer. Following Ernest's schedule, you will just get 3.5 kilometers on the 10th week so it's definitely a no. Denise's schedule, on the other hand, would get you to 5.5 kilometers on week 10 so her training schedule should be followed.
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7BW%7D%20%3D%202" id="TexFormula1" title="\sqrt[4]{W} = 2" alt="\sqrt[4]{W} = 2
solmaris [256]

Answer:

<h2>W = 16</h2>

Step-by-step explanation:

<h3>\sqrt[4]{W}  = 2 </h3>

To find W raise each of the sides of the equation to the power 4 to make W stand alone

That's

<h3>( { \sqrt[4]{W} })^{4}  =  {2}^{4}</h3>

We have

W = 2⁴

We have the final answer as

<h3>W = 16</h3>

Hope this helps you

6 0
3 years ago
A real estate agent has 12 properties that she shows. She feels that there is a 30% chance of selling any one property during a
Ronch [10]

Answer:

0.2528 = 25.28% probability of selling no more than 2 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either they are sold, or they are not. The chance of selling any one property is independent of selling another property, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A real estate agent has 12 properties that she shows.

This means that n = 12

She feels that there is a 30% chance of selling any one property during a week.

This means that p = 0.3

Compute the probability of selling no more than 2 properties in one week.

2 or less sold, which is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.3)^{0}.(0.7)^{12} = 0.0138

P(X = 1) = C_{12,1}.(0.3)^{1}.(0.7)^{11} = 0.0712

P(X = 2) = C_{12,2}.(0.3)^{2}.(0.7)^{10} = 0.1678

Then

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0138 + 0.0712 + 0.1678 = 0.2528

0.2528 = 25.28% probability of selling no more than 2 properties in one week.

8 0
3 years ago
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