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Dominik [7]
4 years ago
8

Near the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of

3.50 m/s, and the second a velocity of 4.20 m/s. What is the velocity of the second runner relative to the first?
Physics
1 answer:
vovangra [49]4 years ago
5 0

Answer:

0.7 m/s

Explanation:

velocity of first runner = 3.5 m/s

velocity of second runner = 4.20 m/s

Both the runner are running in the same direction

velocity of second runner with respect to first runner = velocity of second runner - velocity of first runner

velocity of second runner with respect to first runner = 4.20 - 3.5 = 0.7 m/s

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Explanation:

Given that,

Angle by the normal to the slip α= 60°

Angle by the slip direction with the tensile axis β= 35°

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Applied stress = 12 MPa

We need to calculate the shear stress applied at the slip plane

Using formula of shear stress

\tau=\sigma\cos\alpha\cos\beta

Put the value into the formula

\tau=12\cos60\times\cos35

\tau=4.91\ MPa

Since, the shear stress applied at the slip plane is less than the critical resolved shear stress

So, The crystal will not yield.

Now, We need to calculate the applied stress necessary for the crystal to yield

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\sigma=\dfrac{\tau_{c}}{\cos\alpha\cos\beta}

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Hence, This is the required solution.

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