Complete Question
A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?
Answer:


Explanation:
From the question we are told that
Mass of ball 
Length of string 
Wind force 
Generally the equation for
is mathematically given as




Max angle =
Generally the equation for max Height
is mathematically given as



Generally the equation for Equilibrium Height
is mathematically given as



Answer:
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Explanation:
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Answer:
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Insulator: rubber, glass
Answer:
<em>The displacement of the object is -8 m</em>
Explanation:
<u>Displacement</u>
The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.
If the area is below the y-axis, then the displacement is negative. Otherwise is positive.
It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.
From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.
The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

The displacement of the object is -8 m