A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples a
1 answer:
Answer:
B) 8 T.
Explanation:
For an ideal gas , the gas law that it follow is as follows
P₁V₁ / T₁ = P₂ V₂ /T₂
This law is followed by all the gases whether mono atomic or diatomic.
In this case following information are given
P₂ / P₁ = 3
V₂ / V₁ = 3
T₁ = T
T₂ = ?
From the gas law formula given , we have
= 3 X 3 T
= 9 T
Change in temperature = 9T - T = 8 T.
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Answer:
120°
Explanation:
Draw a free body diagram. There are three forces acting on the traffic light. Two tension forces acting along the cables, and weight.
The tension forces have an angle θ between them. That means each tension force forms an angle of θ/2 with respect to the vertical. So the y component of each tension force is:
Ty = T cos (θ/2)
Sum of the forces in the y direction:
∑F = ma
Ty + Ty − W = 0
2 Ty = W
Substituting:
2 T cos (θ/2) = W
If W = T, then:
2 W cos (θ/2) = W
2 cos (θ/2) = 1
cos (θ/2) = 1/2
θ/2 = 60°
θ = 120°
Answer:
a) 1.06*10^-5
b) 0.00105 °C^-1
Explanation:
Given that
Length of the cylinder, L = 1.5 m
Radius of the cylinder, r = 0.25 cm
Voltage across the rod, V = 15 V
I• at Temperature T• = 20° C is 18.5 A
I at Temperature T = 90° C is 17.2 A
See attachment for calculations
