Question

A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples and its volume also triples. What is the change in the temperature (ΔT) of the gas, in Kelvins? (A)T (B) 8T (C) 9T (D) T/9 (E) T/8

Answer 1

Answer:

B) 8 T.

Explanation:

For an ideal gas , the gas law that it follow is as follows

P₁V₁ / T₁ = P₂ V₂ /T₂

This law is followed by all the gases whether mono atomic or diatomic.

In this case following information are given

P₂ / P₁ = 3

V₂ / V₁ = 3

T₁ = T

T₂ = ?

From the gas law formula given , we have

$T_2 =\frac{P_2\times V_2\times T_1}{P_1\times V_1}$

$V_2 = \frac{P_2}{P_1} \times\frac{V_2}{V_1}\times T$

= 3 X 3 T

= 9 T

Change in temperature = 9T - T = 8 T.