If h(x)=6-x,which is the value of (h*h)(10)

Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com

Ymorist [56]

Answer:

a) $183-1.984\frac{20}{\sqrt{100}}=179.032$

$183+1.984\frac{20}{\sqrt{100}}=186.968$

So on this case the 95% confidence interval would be given by (179.032;186.968)

b) $190-1.984\frac{23}{\sqrt{100}}=185.437$

$190+1.984\frac{23}{\sqrt{100}}=194.563$

So on this case the 95% confidence interval would be given by (185.437;194.563)

c) For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Part a : Summer

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=100-1=99$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that $t_{\alpha/2}=1.984$

Now we have everything in order to replace into formula (1):

$183-1.984\frac{20}{\sqrt{100}}=179.032$

$183+1.984\frac{20}{\sqrt{100}}=186.968$

So on this case the 95% confidence interval would be given by (179.032;186.968)

Part b: Winter

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=100-1=99$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that $t_{\alpha/2}=1.984$

Now we have everything in order to replace into formula (1):

$190-1.984\frac{23}{\sqrt{100}}=185.437$

$190+1.984\frac{23}{\sqrt{100}}=194.563$

So on this case the 95% confidence interval would be given by (185.437;194.563)

Part c

For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

5 0

3 years ago

What is the slope of the line that had that equation 4x+2y=12

Naddik [55]

Answer:

Step-by-step explanation:

The slope intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the equation of a line in the standard form

$Ax+By=C$

Convert to the slope-intercept form:

$4x+2y=12$ subtract 4x from both sides

$2y=-4x+12$ divide both sides by 2

$y=-2x+6$

Therefore the slope is equal to -2.

Other method:

If we have the equation of a line in standard form Ax + By = C

or in general form Ax + By + C = 0, then the formula of a slope is

$m=-\dfrac{A}{B}$

We have A = 4 and B = 2. Substitute:

$m=-\dfrac{4}{2}=-2$

7 0

3 years ago

Help please! Math Nation Section 6 Test Yourself Practice Tool.

aalyn [17]

Answer: D) $y=-5(x-5)^2+1125$

Step-by-step explanation:

Let x be the number of $2 increases in price and y be the revenue.

By using the given table , lets check all the options

A) $y=(x+5)^2-1125$

For x=1, y=1045

$y=(1+5)^2-1125=36-1125=-1089\\\\But\ 1045\neq-1089$

B) $y=(x-5)^2+1125$

For x=1, y=1045

$y=(1-5)^2+1125=14+1125=1139\\\But\ 1045\neq1139$

C) $y=-5(x+5)^2-1125$

$y=-5(1+5)^2-1125=-5(36)-1125=-1305\\\\But\ 1045\neq-1305$

D) $y=-5(x-5)^2+1125$

$y=-5(1-5)^2+1125=-5(16)+1125=1045$

Hence, this is the quadratic equation that models the data.

3 0

3 years ago

Read 2 more answers

Here are The ingredients For makeing fish pie for 6 people.180g flour 240 g fish 80g butter 4 eggs 180 ml milk.

GenaCL600 [577]

The amount of ingredients are needed:

For 2 people: Flour = 60 g, Fish = 80 g, Butter = 26 $\frac{2}{3}$ g, Eggs = 2 eggs, Milk = 60 ml

For 15 people:Flour = 450 g, Fish = 600 g, Butter = 200 g, Eggs = 10 eggs, Milk = 450 ml

Step-by-step explanation:

Given,

For 6 people following things are needed:

Flour = 180 g

Fish = 240 g

Butter = 80 g

Eggs = 4

Milk = 180 ml

To find the amount of ingredients for a) 2 people b) 15 people

Now,

a) For 2 people

Since the number of people decreased by $\frac{1}{3}$ rd times

The amount of ingredients will be decreased by $\frac{1}{3}$ times

So, following this are needed:

Flour = 180× $\frac{1}{3}$ = 60 g

Fish = 240× $\frac{1}{3}$ = 80 g

Butter = 80× $\frac{1}{3}$ = 26 $\frac{2}{3}$ g

Eggs = 4× $\frac{1}{3}$ = 1 $\frac{1}{3}$ = 2 eggs

Milk = 180× $\frac{1}{3}$ = 60 ml

b) For 15 people

Since the number of people increased by $\frac{5}{2}$ th times

The amount of ingredients will be decreased by $\frac{5}{2}$ th times

So, following this are needed:

Flour = 180× $\frac{5}{2}$ = 450 g

Fish = 240× $\frac{5}{2}$ = 600 g

Butter = 80× $\frac{5}{2}$ = 200 g

Eggs = 4× $\frac{5}{2}$ = 10 eggs

Milk = 180× $\frac{5}{2}$ = 450 ml

8 0

3 years ago

The least common multiple is the blank multiple, other than 0, common to sets of multiples.

Tomtit [17]

It would be it is the smallest multiple

8 0

3 years ago