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sergejj [24]
3 years ago
15

A saleswoman is paid $80 a day plus $6 for each sale she makes. She wants to earn more than $150 today. Write an inequality that

represents the number of sales, x, the saleswoman must make today to earn more than $150. What is the least number of sales she must make to reach her sales goal
Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

12

Step-by-step explanation:

Given that:

Daily wages paid to a saleswoman = $80

Wages paid for each sale made by her = $6

Target of today's earnings = more than $150

To find:

Least number of sales to be made so that the total earnings today is more than $150.

Solution:

Number of sales for today = x

Wages for one sale = $6

Wages for x number of sales = $6x

Total earnings = Per day sales + Wages for x number of sales > $150

80 + 6x > 150

we need to solve for above inequality to find the least number of sales to be made to meet the goal.

Subtracting 80 from both sides:

\Rightarrow 6x>70\\

Dividing both sides by 6:

\Rightarrow x > 11

Therefore, <em>at least 12 sales</em> must be made.

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Step-by-step explanation:

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Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

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Answer:

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Step-by-step explanation:

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