Question

A saleswoman is paid $80 a day plus $6 for each sale she makes. She wants to earn more than $150 today. Write an inequality that represents the number of sales, x, the saleswoman must make today to earn more than $150. What is the least number of sales she must make to reach her sales goal

Answer 1

Answer:

12

Step-by-step explanation:

Given that:

Daily wages paid to a saleswoman = $80

Wages paid for each sale made by her = $6

Target of today's earnings = more than $150

To find:

Least number of sales to be made so that the total earnings today is more than $150.

Solution:

Number of sales for today = $x$

Wages for one sale = $6

Wages for $x$ number of sales = $6$x$

Total earnings = Per day sales + Wages for $x$ number of sales > $150

$80 + 6x > 150$

we need to solve for above inequality to find the least number of sales to be made to meet the goal.

Subtracting 80 from both sides:

$\Rightarrow 6x>70$

Dividing both sides by 6:

$\Rightarrow x > 11$

Therefore, at least 12 sales must be made.