A saleswoman is paid $80 a day plus $6 for each sale she makes. She wants to earn more than $150 today. Write an inequality that
1 answer:
Answer:
12
Step-by-step explanation:
Given that:
Daily wages paid to a saleswoman = $80
Wages paid for each sale made by her = $6
Target of today's earnings = more than $150
To find:
Least number of sales to be made so that the total earnings today is more than $150.
Solution:
Number of sales for today =
Wages for one sale = $6
Wages for number of sales = $6
Total earnings = Per day sales + Wages for number of sales > $150
we need to solve for above inequality to find the least number of sales to be made to meet the goal.
Subtracting 80 from both sides:
Dividing both sides by 6:
Therefore, <em>at least 12 sales</em> must be made.
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The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.