Let
x-------> the length side of the original square garden
Step 1
<u>Find the value of x</u>
we know that

taking square root both sides




the solution is

therefore
<u>the answer Part a) is</u>
The original length side of the square garden is 
Step 2
<u>Find the area of the original square garden</u>
we know that
the area of the original square garden is equal to

substitute the value of x in the formula

therefore
<u>the answer part b) is</u>
the area of the original square garden is 
Answer:43
Step-by-step explanation:just Calculate all the numbers
Answer:
m=-4 b=4
Step-by-step explanation:
the slope of the line is 4x+y=4
and the y-intercept is 4