Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways = 
=126
= 
=
Answer:
the third one
Step-by-step explanation:
bc like there are 2 boxes of 1 and 5 boxes of 1/6 so thats already 2 and 5/6 which applies to all of them. then there is 1 box of 1 and 2 boxes of 1/3 so thats 1 and 1/3 which applies to all of them also but when you make them have the same denominator you get 2 and 5/6 + 1 and 4/6 which deletes the second one. When you add you should get the same denominator so that deletes the first one so then you simplify that and the fraction should still be equal to the unsimplified fraction so you should get 4 and 1/2 if that makes sense
The answer is:
D. Ac = {xΙx ∈ U and is an even positive integer}
:)
Answer:
A (0,3)
Step-by-step explanation:
The given trapezoid has vertices:
(0,6), (7,12), (7,9) and (0,12).
We want to choose from the given options, a point that is a vertex for the image produced by a dilation about the origin with a scale factor of 1/2.
Note that the mapping for such a dilation is:
This implies that:
Therefore correct choice is (0,3)
One way to do this is use the fact that the exterior angles of all polygons add up to 360 degrees
So an exterior angle of a regular octagon = 360 / 8 = 45 degrees.
So each interior angle = 180 - 45 = 135 degrees
so total measure of all angles in octagon = 8 * 135 = 1080 degrees
