Answer:
9.6J+88.2J=97.8J
Explanation:
Here the velocity of the seagull is given,mass is given and its height.
We have to find its mechanical energy my friend.
Mechanical energy=kinetic energy + potential energy.
First we will find kinetic energy.
For calculating kinetic energy we need mass and velocity,which are given here.
So, Ek=
So by substituting the values we get 9.6J.
Now we find the potential energy which is mgh.
By substituting the values we get 88.2J.
Then we add both of those and get 97.8J
I hope this satisfies you and make sure you contact me if it doesn't
Answer:
Explanation:
Component of force perpendicular to stick
= F Sin 60°
=√3 / 2 F.
Taking torque about the other end
= √3 / 2 F x 1 Nm
Weight of stick = 60 gm
= 60 x 10⁻³ kg
= 60 x 10⁻³ x 9.8 N
= .588 N
This weight will act from the middle point of stick so torque about the
other end
= .588 x 1 Nm
Balancing these two torques we have
.588 = √3 /2 F
F = 0.679 N
Explanation:
Given that,
Initial velocity, u = 11.3 m/s
Angle above the horizontal, 
Time of flight :
Horizontal distance traveled is given by :
x = ut
x = 11.3 m/s × 1.32 s
x = 14.916 m
Maximum height is given by :
Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.
Answer:
true can i get brainliest :)
Explanation:
Answer:
i) 3.514 s, ii) 5.692 m/s
Explanation:
i) We can use Newton's second law of motion to find out how long does it take for the Eagle to touch down.
as the equation says for free-falling
h = ut +0.5gt^2
Here, h = 10 m, g = acceleration due to gravity = 1.62 m/s^2( on moon surface)
initial velocity u = 0
10 = 0.5×1.62t^2
t = 3.514 seconds
Therefore, it takes t = 3.514 seconds for the Eagle to touch down.
ii) use Newton's 1st equation of motion to calculate the velocity of the lunar module when it hits the surface of the moon
v = u + gt
v = 0+ 1.62×3.514
v= 5.692 m/s
