10/70×360°
=51.4°
hope thus helps
Answer:
Explanation:
The question, translated, is:
- <em>A steel ball rolls and falls off the edge of a table from 4ft above the floor. If you hit the ground 5ft from the base of the table, what was your initial horizontal velocity?</em>
<em />
<h2>Solution</h2>
<em />
This is a projectile motion, for which, the equations that you will need are:
<u />
<u>1. Calculate the time that it takes the ball to fall 4ft</u>
<u />
<u>2. Calculate the horizontal velocity:</u>
Answer:
63360 mi/h
Explanation:
<u>How to find the speed of an object</u>
Calculate speed, distance, or time using the formula d = st, distance equals speed times time. The Speed Distance Time Calculator can solve for the unknown SDT value given two known values.
Time can be entered or solved for in units of second S (s), minutes (min), hours (hr), or hours and minutes and seconds (hh:mm: ss). See shortcuts for time formats below.
To solve for distance use the formula for distance D = st, or distance equals speed times time.
distance = speed x time
Rate and speed are similar since they both represent some distance per unit time like miles per hour or kilometers per hour. If rate r is the same as speed s, r = s = d/t. You can use the equivalent formula d = rt which means distance equals rate times time.
distance = rate x time
To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time.
speed = distance/time
To solve for time use the formula for time, t = d/s which means time equals distance divided by speed.
time = distance/speed
Therefore, the speed = 63360 miles per hour
= 63360 mi/h
Answer:
F_net = B -W
The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet
Explanation:
A hot air balloon is subjected to the force of its weight directed towards the center of the Earth. The thrust due to the cold air released, this thrust is directed upwards.
If we assume that the balloon rises at a constant speed
F_net = B -W
F_neta = ρ g V_body - ρ_body g V_body
The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet
This problem can be solved based on the rule of energy conservation, as the energy of the photon covers both the energy needed to overcome the binding energy as well as the energy of ejection.
The rule can be written as follows:
energy of photon = binding energy + kinetic energy of ejectection
(hc) / lambda = E + 0.5 x m x v^2 where:
h is plank's constant = 6.63 x 10^-34 m^2 kg / s
c is the speed of light = 3 x 10^8 m/sec
lambda is the wavelength = 310 nm
E is the required binding energy
m is the mass of photon = 9.11 x 10^-31 kg
v is the velocity = 3.45 x 10^5 m/s
So, as you can see, all the parameters in the equation are given except for E. Substitute to get the required E as follows:
(6.63x10^-34x3x10^8)/(310x10^-9) = E + 0.5(9.11 x 10^-31)(3.45x10^5)^2
E = 6.41 x 10^-16 joule
To get the E in ev, just divide the value in joules by 1.6 x 10^-19
E = 4.009 ev
