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Finger [1]
3 years ago
11

If a body is accelerating m change the velocity of 2 metre per second square when it was acted by five hundred Newton of force t

hen calculate its mass.
​
Physics
2 answers:
WARRIOR [948]3 years ago
5 0
  • Force=500N
  • Acceleration=2m/s^2

using newtons law

\\ \rm\Rrightarrow Force=Mass(Acceleration)

\\ \rm\Rrightarrow Mass=\dfrac{Force}{Acceleration}

\\ \rm\Rrightarrow Mass=\dfrac{500}{2}

\\ \rm\Rrightarrow Mass=250kg

Thepotemich [5.8K]3 years ago
5 0

Answer:

Here is something that might surprise you: if you weigh 2m, not only is the Earth attracting you with a force of 500m, but you are attracting the Earth with a force of 500m too.

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Didn't know what type of science it was? But pls helpp
Alla [95]
The answer is the third one down. New evidence may contradict the old evidence of a certain theory.
8 0
3 years ago
Use the following information for question 26 and 27. A 550-g ball traveling at 8.0 m/s undergoes a sudden head-on perfectly ela
Gnoma [55]

Answer:

The speed of 250 g ball after collision is 14 m/s.

Explanation:

mass of first ball, m = 550 g = 0.55 kg

initial velocity of first ball,  u = 8 m/s

mass of second ball, m' = 250 g = 0.25 kg

initial velocity of second ball, u' = - 8 m/s

Let the speed of the balls is v and v' after the collision.

Use conservation of momentum

m u + m' u' = m v + m' v'

0.55 x 8 - 0.25 x 8 = 0.55 v + 0.25 v'

0.55 v + 0.25 v' = 2.4 ..... (1)

Use the formula  of coefficient of restitution,

For elastic collision, e = 1

e =\frac{v'-v}{u - u'}\\\\1 =\frac{v'-v}{8+8}\\\\16 =v' - v...... (2)

By solving (1) and (2)

v = - 2 m/s and v' = 14 m/s

6 0
3 years ago
Which of the following is how the substance in a longitudinal wave flows?
cricket20 [7]

Answer:

The answer is <em>D. In the direction of the wave</em>

Explanation:

I took the test, hope this helps! :)

3 0
3 years ago
How many revolutions per minute would a 25 m -diameter ferris wheel need to make for the passengers to feel "weightless" at the
kozerog [31]
Refer to the diagram shown below.

Let ω =  the angular velocity (rad/s) of the wheel.

At the topmost point, the passenger, with mass m,  will feel weightless if the passenger's weight matches the centripetal force.
The passenger's weight is mg.
The centripetal force is mω²r.

Therefore
mω²r = mg
ω = √(g/r)

Because g = 9.8 m/s² and r = 25/2 = 12.5 m, therefore
ω = √(9.8/12.5) = 0.8854 rad/s

Because 1 revolution per second is 2π rad/s, therefore
\omega = (0.8854 \,  \frac{rad}{s} )*( \frac{1}{2 \pi} \,  \frac{rev}{rad} )*(60 \,  \frac{s}{min} ) = 8.455 \, rev/min

Answer: 8.455 rev/min

8 0
3 years ago
Measurements of how orbital speeds depend on distance from the center of our galaxy tell us that stars in the outskirts of the g
diamong [38]

Answer:

True

Explanation:

Measurements of how orbital speeds depend on distance from the center of our galaxy tell us that stars in the outskirts of the galaxy. True or False

stars in the outskirt orbit the galactic center

the object mean orbital speed depends only on the Earth's mass and the semi-major axis (half the longest diameter) of the object's orbit. worthy of note. the orbital speed changes depending on where in the orbit the object is. It will be greatest when closest to Earth and least when furthest from Earth.

5 0
3 years ago
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