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3 years ago

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If a body is accelerating m change the velocity of 2 metre per second square when it was acted by five hundred Newton of force t

hen calculate its mass.

2 answers:

WARRIOR [948]3 years ago

5 0

Force=500N
Acceleration=2m/s^2

using newtons law

$\\ \rm\Rrightarrow Force=Mass(Acceleration)$

$\\ \rm\Rrightarrow Mass=\dfrac{Force}{Acceleration}$

$\\ \rm\Rrightarrow Mass=\dfrac{500}{2}$

$\\ \rm\Rrightarrow Mass=250kg$

Thepotemich [5.8K]3 years ago

5 0

Answer:

Here is something that might surprise you: if you weigh 2m, not only is the Earth attracting you with a force of 500m, but you are attracting the Earth with a force of 500m too.

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What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms?

Nitella [24]

We already know the formula:
Voltage = Current * Resistance
In the given question, there are numerous information's that are already given.
Current = 6.2 A
Resistance = 18 ohms
Then
Voltage = 6.2 * 18 Volts
= 111.6 Volt
So, the voltage in the circuit will be 111.6 volts. I hope it helps you.

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4 years ago

Describe the role of the teacher and the learner in a natural science and technology classroom

dem82 [27]

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3 years ago

Giving a test to a group of students, the grades and gender are summarized belowGrades vs. Gender ABCMale10316Female465If one st

strojnjashka [21]

Answer:

20.45%

Explanation:

The probability that the student got a B is

$\frac{total\#of\text{ students that got B}}{\text{total students }}\times100\%$

Now, how many students are there in total?

The answer is

$10+3+16+4+6+5=44\; \text{students}$

How many students got a B?

The answer is

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therefore, the probability that the student has got a B is

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1 year ago

If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a

Lilit [14]

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7 0

3 years ago

Read 2 more answers

What, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is 5.66 0.09 m?

iren2701 [21]

Answer:

4.77 %

Explanation:

We know that the volume V for a sphere of radius r is

$V(r) = \frac{4}{3} \ \pi \ r^3$

If we got an uncertainty $\Delta r$ the formula for the uncertainty of V is:

$\Delta V(r) = \sqrt{ (\frac{dV}{dr} \Delta r)^2 }$

We can calculate this uncertainty, first we obtain the derivative:

$\frac{dV}{dr} = 3 * \frac{4}{3} \ \pi \ r^2$

$\frac{dV}{dr} = 4 \ \pi \ r^2$

And using it in the formula:

$\Delta V(r) = \sqrt{ (4 \ \pi \ r^2\Delta r)^2 }$

$\Delta V(r) = \sqrt{ 4^2 \ \pi^2 \ r^4 \Delta r^2 }$

$\Delta V(r) = 4 \ \pi \ r^2 \Delta r$

The relative uncertainty is:

$\frac{\Delta V(r)}{V(r)}$

$\frac{ 4 \ \pi \ r^2 \Delta r }{ \frac{4}{3} \ \pi \ r^3}$

$\frac{ 3 \Delta r }{ r}$

Using the values for the problem:

$\frac{ 3 * 0.09 m }{ 5.66 m} = 0.0477$

This is, a percent uncertainty of 4.77 %

4 0

3 years ago