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Finger [1]
2 years ago
11

If a body is accelerating m change the velocity of 2 metre per second square when it was acted by five hundred Newton of force t

hen calculate its mass.
​
Physics
2 answers:
WARRIOR [948]2 years ago
5 0
  • Force=500N
  • Acceleration=2m/s^2

using newtons law

\\ \rm\Rrightarrow Force=Mass(Acceleration)

\\ \rm\Rrightarrow Mass=\dfrac{Force}{Acceleration}

\\ \rm\Rrightarrow Mass=\dfrac{500}{2}

\\ \rm\Rrightarrow Mass=250kg

Thepotemich [5.8K]2 years ago
5 0

Answer:

Here is something that might surprise you: if you weigh 2m, not only is the Earth attracting you with a force of 500m, but you are attracting the Earth with a force of 500m too.

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svetoff [14.1K]

Answer:

Explanation:

There are two hypotheses she could test:

A cat's heart rate changes while it is napping.

A cat's heart rate does not change while it is napping.

3 0
3 years ago
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A 200 N trash can is pulled across the sidewalk by a person at constant speed by a force of 75 N. What is the coefficient of fri
Pavel [41]

Answer:

μ = 0.375

Explanation:

F = Applied force on the trash can = 75 N

W = weight of the trash can = 200 N

f = frictional force acting on trash can

Since the trash can moves at constant speed, force equation for the motion of can is given as

F - f = 0

75 - f = 0

f = 75 N

μ = Coefficient of friction

frictional force is given as

f = μ W

75 = μ (200)

μ = 0.375

5 0
2 years ago
How does the matter and (solar) energy move through the sphere?
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5 0
2 years ago
Is god real??? i wanna know
NemiM [27]
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6 0
3 years ago
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A vertical block-spring system on earth has a period of 6.0 s. What is the period of this same system on the moon where the acce
Vera_Pavlovna [14]

Answer:

D) 15s

Explanation:

let Te be the period of the block-spring system on earth and Tm be the period of the same system on the moon.let g1 be the gravitational acceleration on earth and g2 be the gravitational acceleration on the moon.

the period of a pendulum is given by:

T = 2π√(L/g)

so on earth:

Te = 2π√(L/g1)

     =  6s

on the moon;

Tm = 2π√(L/g2)

since g2 = 1/6 g1 then:

Tm = 2π√(L/(1/6×g1))

      = √(6)×2π√(L/(g1))

and 2π√(L/(g1)) = Te = 6s

Tm = (√(6))×6 = 14.7s ≈ 15s

Therefore, the period of the block-spring system on the moon is 15s.

5 0
3 years ago
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