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kati45 [8]
3 years ago
5

For the circuit shown, which of the following is true?

Physics
2 answers:
liraira [26]3 years ago
6 0
You can't tell the relative values of I-1 and I-2 from the information given,
but that's not for any super-technical reason. 

The reason is because the drawing doesn't show WHERE in the circuit
I-1 and I-2 are measured. 

It makes a BIG difference if they're the currents in the resistors, or
the currents in and out of the battery.

-- The currents in and out of the battery are equal.

-- The current through either resistor is less than
the current in or out of the battery.

-- The sum of the currents through both resistors
is equal to the current in or out of the battery.

-- The currents through the two resistors may be equal
or unequal, and either one may be greater or less than
the other.  It all depends on the values of the resistors.
oksian1 [2.3K]3 years ago
6 0
The best and most correct answer among the choices provided by the question is the first choice.

The statement "<span>You cannot tell the relative values of I from the information given." among the given choices.</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
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Which scenario is an application of Newtons Second Law of Motion?
svlad2 [7]
D would be the answer because The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
4 0
3 years ago
A field measuring 12 meters by 16 meters is to have a brick paver walkway installed all around it, increasing the total area to
kolezko [41]

Answer:

1.5 m

Explanation:

Length. L = 12 m

Width, W = 16 m

Area, A = 12 x 16 = 192 m^2

Let the width of pavement be d.

The new length, L' = 12 + 2d

the new width, W' = 16 + 2d  

New Area, A' = L' x W' = (12 + 2d)(16 + 2d) = 192 + 56 d + 4d^2

Difference in area = A' - A

285 =  192 + 56 d + 4d^2 - 192

93 =  56 d + 4d^2

4d^2 + 56 d - 93 = 0

d = \frac{-56\pm \sqrt{56^{2}+4\times 4\times 93}}{8}

d=\frac{-56\pm 87.72}{8}\

d = 1.5 m

Thus, the width of the pavement is 1.5 m.

6 0
3 years ago
Rahul and Sonia were playing with blocks and each of them made a train out of them. Both of them thought of measuring the length
lozanna [386]

Answer:

They measured their train using their handspan

7 0
3 years ago
When two ions form a bond, the overall charge of that compound will ALWAYS become..
Maslowich

Answer:

C. Neutral

Explanation:

Ions will combine in a way that the overall ionic compound will always be neutral.

8 0
3 years ago
A spacecraft is moving past the earth at a constant speed of 0.60 times the speed of light. The astronaut measures the time inte
Afina-wow [57]

Answer:

the time interval that an earth observer measures is 4 seconds

Explanation:

Given the data in the question;

speed of the spacecraft as it moves past the is 0.6 times the speed of light

we know that speed of light c = 3 × 10⁸ m/s

so speed of spacecraft v = 0.6 × c = 0.6c

time interval between ticks of the spacecraft clock Δt₀ = 3.2 seconds

Now, from time dilation;

t = Δt₀ / √( 1 - ( v² / c² ) )

t = Δt₀ / √( 1 - ( v/c )² )

we substitute

t = 3.2 / √( 1 - ( 0.6c / c )² )

t = 3.2 / √( 1 - ( 0.6 )² )

t = 3.2 / √( 1 - 0.36 )

t = 3.2 / √0.64

t = 3.2 / 0.8

t = 4 seconds

Therefore, the time interval that an earth observer measures is 4 seconds

6 0
3 years ago
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