Answer:
B i think is the answer
Explanation:
i feel like it is B because if you put them together and the answer is 1.5 so it is B
Answer:
V = 8.34m/s
Explanation:
Given that
1/2ke^2 = 1/2mv^2 ......1
Where e = 3.75cm = (3.75/100)m
e = 0.0375m
K = 500 N/m
m = 10g = 10/1000
= 0.01kg
Substitute the values into equation 1
0.5×500×(0.0375)^2 = 0.5×0.01×v^2
250×0.001395 = 0.005v^2
0.348 = 0.005v^2
v^2 = 0.348/0.005
v^2 = 69.6
V = √69.6
V = 8.34m/s
The ball launches at the speed of V = 8.34m/s
Answer: 0.213m
Explanation: The fundamental frequency is 805Hz.
The second harmonic (first overtone ) is 1035 Hz and the third harmonic (second overtone) is 1265 Hz.
The pipe is an air filled hence it is a closed pipe
Recall that v = f λ
At fundamental frequency
Where v = speed of sound in air (v) = 343 m/s
Fundamental frequency (f) = 805 Hz
Wavelength ( λ) = ?
By substituting the parameters, we have that
343 = 805 × λ
λ = 343 / 805
λ = 0.426m
The pipe is an open one and at the fundamental frequency, hence the relationship between wavelength ( λ) and length of air is given as
L = λ/4
But λ = 0.426m
L = 0.426/2
L = 0.213m
