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yulyashka [42]
4 years ago
11

Locate the element helium (He) on the periodic table. What is the period number in which helium is found? What is the group name

in which helium is found?
Physics
2 answers:
Digiron [165]4 years ago
8 0

period 1 and group 18 or 8A

Nat2105 [25]4 years ago
8 0

Answer:

Period: 1

Group: 18

Explanation:

Helium has a period no. 1 and found in the group 18. Group 18 consists of Noble gases. It has atomic no. 2. It is named after Greek name of Sun i.e. Helios. An interesting fact about Helium is it was discovered on Sun before Earth. It was discovered during the spectral analysis of Eclipsed Sun in 1868 by Capt. C T Haig, Geroges Rayet, Normon Pogson, and Lt. John Herschel. It is odorless, colorless, non toxic, tasteless and inert gas.

It is the second most abundant element in the observable universe, hydrogen being the most abundant.

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A 2.00-kilogram object weighs 19.6 newtons on earth. if the acceleration due to gravity on mars is 3.71 meters per second2, what
Harrizon [31]
Recall that mass is the amount of matter present in a body. That means it's a property that is consistent regardless of the body's current location, gravity's pull on the body, etc. 

Let's not confuse mass with weight (which is a force computed as Weight = mass x acceleration). Mass will remain constant and that means that whether the object is on Earth or on Mars, its mass remains the same.  Thus, the object will still have 2.00 kg as mass on Mars. 

Answers: 2.00 kilograms
4 0
4 years ago
A missile is moving 1350 m/s at a 25.0° angle. It needs to hit a target 23,500 m away in a 55.0° direction in 10.20 s. What is d
QveST [7]

Answer:

  The target's velocity is about 1320 m/s in the direction 265.7°.

Explanation:

In order for there to be a collision between missile and target, we must have ...

  (target starting position) + (target movement) = (missile movement)

assuming the missile starts from the origin of all measurements. The missile moves 10.2 seconds before impact, so moves a distance of ...

  (10.2 s)(1350 m/s) = 13,770 m

__

We are interested in the target movement, so we can solve for that:

  (target movement) = (missile movement) - (target starting position)

In terms of meters, this is ...

  (target movement) = 13770∠25° - 23500∠55° ≈ 13467.74∠-94.3°

The target covers this distance in the same 10.2 seconds before collision, so its speed is (13467.74 m)/(10.2 s) ≈ 1320.4 m/s.

As a positive angle, the target's direction is ...

  -94.3° +360° = 265.7°

The direction of the target's velocity is 265.7°.

_____

If you're calculating this by hand, there are a couple of ways you can do it. You can convert to rectangular coordinates and back (perhaps least confusing), or you can use the law of cosines to solve the triangle, then translate angles back to the x-y coordinate plane.

Using rectangular coordinates, we have ...

  13770∠25° = 13770(cos(25°), sin(25°)) ≈ (12479.9, 5819.45)

  23500∠55° = 23500(cos(55°), sin(55°)) ≈ (13479.0, 19250.1)

Then the difference is ...

  (12479.9, 5819.45) -(13479.0, 19250.1) ≈ (-999.188, -13430.6)

and the (3rd-quadrant) angle is ...

  target direction = arctan(-13430.6/-999.188) ≈ -94.3° = 265.7°

__

The target's speed is found by dividing the distance it covers by the time it takes.

  √(13430.6² +999.188²)/10.2 ≈ 1320.36 . . . m/s

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