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Alex17521 [72]
4 years ago
11

What would you do to change the volume of gas?

Physics
1 answer:
valentinak56 [21]4 years ago
4 0

The only way to do that is to reduce the
volume of the container the gas is in.

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Kim designed an experiment to show how heat can be transferred from one place to another. The steps of the experiment are shown
Radda [10]
Heat transfer by conduction, since kim is trying to show that heat travels from one end of the rod to the other. This is nothing but conduction
3 0
3 years ago
You ride on an elevator that is moving with constant upward acceleration while standing on a bathroom scale. the reading on the
Blababa [14]

The reading on the scale is greater than your actual weight.

4 0
4 years ago
What is the angle θ between vectors A⃗ and B⃗ if A⃗ =4ı^−4ȷ^ and B⃗ =−5ı^+7ȷ^?
ololo11 [35]

The characteristics of the scalar product allows to find the angle between the two vectors is:

  • The angle θ = 170º

The scalar product is the product between two vectors whose result is a scalar.

            A . B = |A|  |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

            i.i = j.j = 1

            i.j = 0

            A . B = (4 i - 4j). * -5 i + 7j)

            A . B = - 4 5 - 4 7

            A. B = -48

We look for the modulus of each vector.

           |A| = \sqrt{x^2 +y^2 }

           |A| = \sqrt{4^2 + 4^2}  

           |A| = 4 √2

          |B| = \sqrt{5^2 +7^2}

          |B| = 8.60

We substitute.

            -48 = 4√2  8.60  cos θ

            -48 = 48.66 cos θ

            θ = cos⁻¹   \frac{-48}{48.664}  

            θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

  • the angle θ = 170º

Learn more about the scalar product here:  brainly.com/question/1550649

8 0
3 years ago
Choose the best description of the attraction between you and your classmate.
Lerok [7]

Answer:

The correct option is;

D. There is not enough information to answer this question

Explanation:

The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)

For an in between distance of 1 m and equal masses of 60 kg, we have;

F = G \times \dfrac{m_{1}  \times m_{2}}{r^{2}} = 6.67408 \times 10^{-11}  \times \dfrac{60 \times 60}{1^{2}}  \approx  2.403 \times 10^{-7} N

The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.

5 0
3 years ago
What is a reasonable estimate of the average kinetic energy of an athlete during a 100 m race that takes 10s?
arlik [135]
The average weight of an athlete should be around 60kg so from the information that the athlete can run 100m in 10s, we can calculate that their average speed is 10m/s. Using the kinetic energy formula, Ek = 1/2mv^2 we can calculate the kinetic energy using 60kg as the mass.

(1/2)(60)(10^2) = Ek

Ek= 3000J
7 0
3 years ago
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