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marta [7]
4 years ago
6

Can anyone help me do #15 ​

Mathematics
1 answer:
makkiz [27]4 years ago
4 0

She  \: tilled  \: over  \: 2  \: days: 7\frac{2}{12}  + 4 \frac{11}{12}  = 12 \frac{1}{2}  < 15 \frac{7}{12}  \\ \Rightarrow She \: didn't \: till \: enough \: soils, \: she \: need \: 15 \frac{7}{12}  - 12 \frac{1}{12}  = 3 \frac{1}{2}  \: yards \: of \: soils \: more

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Answer:

e

Step-by-step explanation:

yes

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At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st
EastWind [94]

<u>Answer:</u>

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

<u>Step-by-step explanation:</u>

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = \frac{609}{58} = 10.5

Checking for ratios of the given options:

A. \frac{483}{42} =11.5

B. \frac{378}{28} =13.5

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D. \frac{560}{56} =10

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Mixed fraction:

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6 0
3 years ago
How do I solve this out??
GuDViN [60]
<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0
3 years ago
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