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Alex
3 years ago
7

Which of the following functions have a vertical asymptote for values of θ such that cos θ = 1? Select two answers.

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0
Well costheta=1, at 0, 2pi,... 
knowing this we can exclude the first two as the are not undefined anywhere. 
tan is sin/cos, at 0 sin is also 0 so it becomes 0/1 which is 0, not undefined.
sec is1/cos, cos is 1, this is just 1
csc is 1/sin, sin is 0, 1/0 is undefined, meaning there will be an asymptote 
cot is cos/sin, this is again 1/0, so it is also an asymptote
The last two answers are the ones you want
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Do u just plot the numbers on the graph like (1,26)???
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Yes

Step-by-step explanation:

Make sure you plot each number on the right axis. :)

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3 years ago
What is the solution to the system of equations graphed below?<br> y=-4x + 33<br><br> y=5/3x-1
Black_prince [1.1K]

Answer:

x = 6

y = 9

This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. <u>brainly.com/question/13675950</u>

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3 years ago
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What is the value of [-4.6]
solniwko [45]
<h2>Answer:</h2>

              The value is:

                      -4

<h2>Step-by-step explanation:</h2>

We are asked to find the value of the ceiling function: \left \lceil -4.6 \right \rceil

As we know that the ceiling function always occupy the higher value in integers.

i.e. the ceiling function act as follows:

it takes value 0 when   -1< x≤0

                       1 when  0 < x ≤ 1

                       2 when  1 < x ≤2

and so on.

As we know that:

            -4.6 lie between -5 and -4.

            Hence, we have:

            \left \lceil -4.6 \right \rceil=-4

7 0
3 years ago
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Urgent due for tommorow . will mark brainliest and get 50 pts<br>plz show workings​
Vilka [71]

Answer:

Step-by-step explanation:

Sec B

1) 5p⁻³ = 8*5⁻²      

p⁻³  = 2³*5⁻²/5            

p⁻³ =2³*5⁻³             { 1/a^m = a^-m}

p⁻³ = 5⁻³ /2⁻³            {a^m = 1/a^-m}

p⁻³ = (5/2)⁻³

p= 5/2

2) 4x²  = 81

x²  = 81/4

x²  = 9² /2²

x²  =(9/2)²

x = 9/2

3) 9^x/3 =81

9^x/3 = 9^2

Comparing the powers, x/3 = 2

                                         x = 2*3 =6

  x = 6

6 0
3 years ago
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