The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.
2 answers:
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Answer:
Answer D : about 1067 meters
Explanation:
There are two steps to this problem:
1) First find the time it takes the plane to stop using the equation for the acceleration:
Where Vf is the final velocity of the plane (in our case: zero )
Vi is the initial velocity of the plane (in our case: 80 m/s)
is the acceleration (in our case -3 m/s^2 - notice negative value because the velocity is decreasing)
with units corresponding to seconds given the quantities involved in the calculation.
2) Second knowing the time it took the plane to stop, now use that time in the equation for the distance traveled under accelerated motion:
Where the answer results in units of meters given the quantities used in the calculation.
We round this to 1067 meters
Answer:
You should choose airspeed 158.11 km/h at 18.4° west of south
Explanation:
The distance to the air port is 450 km due to south
You should to reach the airport in 3 hours
→ Velocity = distance ÷ time
→ Distance = 450 km , time = 3 hours
→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south
A wind is blowing from west 50 km/h
We need to know what heading and airspeed you should choose to
reach your destination
At first we must find the resultant velocity of your plane and the wind
The south and west are perpendicular, then the resultant velocity is
→
→ km/h ,
km/h
→ km/h
To cancel the velocity of the wind, the pilot should maintain the velocity
of the plane at 158.11 km/h
The direction of the velocity is the angle between the resultant velocity
and the vertical (south)
→ The direction of the velocity is °
The direction of the velocity is 18.4° west of south
<em>You should choose airspeed 158.11 km/h at 18.4° west of south</em>