Answer:
2⋅2⋅2⋅5=40 2 ⋅ 2 ⋅ 2 ⋅ 5 = 40
Let x be the first of the four consecutive numbers.
Then x+1 is the second,
and x+2 is the third,
and x+3 is the fourth.
If their sum is 810, then
x + x+1 + x+2 + x+3 = 810
If you solve that equation for x, you'll have the answer to your question.
Solution:
<u>We know the following rules:</u>
- Rule: If an exponent is negative, it will be in the fraction 1/nˣ.
- Rule: If an exponent is positive, it will be in whole number form and will multiply itself m times.
- Rule: if a number's exponent is 0, then the number is 1.
Now, let's solve each problem.
<u>Question-7</u>
- 4³ = 4 x 4 x 4 = 64
- 4² = 4 x 4 = 16
- 4¹ = 4
- 4⁰ = 1
<u>Question-8</u>
- (-2)³ = (-2) x (-2) x -(2) = -8
- (-2)² = (-2) x (-2) = 4
- (-2)¹ = -2
- (-2)⁰ = 1
Hoped this helped!
We have the equation:
Fist we add the b on the right side of the equation.
For the second step we multiply d to the right side of the equation
