If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
Answer:
Did you ever find the answer? I have the same question!
Step-by-step explanation:
Answer:
<u>There were 12 gold coins in the chest at the start.</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
x = Number of gold coins in a chest
1/2x = Number of gold coins taken by the captain
1/4x = Number of gold coins taken by Sally
3 = Number of gold coins left
2. How many coins were in the chest at the start?
Let's write the following equation to solve for x:
1/2x + 1/4x + 3 = x
2x + x + 12 = 4x (Lowest Common Denominator is 4)
4x - 2x - x = 12 (Like terms)
x = 12
<u>There were 12 gold coins in the chest at the start.</u>
