When the number of electrons decreases, the charge of the atom becomes more positive.
<span>2Al + 3Br2 -------------> 2AlBr3
</span>3 g Al = 0.11 mol Al.
<span>6 g Br2 = 0.0375 mole bromine (it is diatomic). </span>
<span>moles of aluminium will take part in reaction = 0.0375 X (2/3) = 0.025. </span>
<span>Gram-mole of AlBr3 will be produced = 0.025 mole = 6.6682 g.
</span>moles of Al left = 0.11 - 0.025 = 0.086<span>
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